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Yuri [45]
3 years ago
10

Find the common difference of the arithmetic sequence -5, -14, -23, ...

Mathematics
2 answers:
BartSMP [9]3 years ago
5 0

Answer:

-9

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

  • A Arithmetic sequence -5 , -14 , -23 ...

And we need to find out the common difference of the Arithmetic sequence . The common difference of a Arithmetic sequence is the number which is added to a term to obtain the next term of the sequence . And it can be obtained by subtracting the consecutive terms.

<u>Sequence</u><u> </u><u>:</u><u>-</u><u> </u>

:\implies -5 , -14 , -23

<u>Common</u><u> difference</u><u> </u><u>:</u><u>-</u><u> </u>

:\implies CD = -14 -(-5) = -14+5=-9

:\implies CD = -23-(-14) = -23+14=-9

<u>Hence </u><u>the</u><u> </u><u>common</u><u> difference</u><u> </u><u>is </u><u>(</u><u>-</u><u>9</u><u>)</u><u> </u><u>.</u>

Vlada [557]3 years ago
4 0
-9 is the right answer I hope you do great
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If 5x is a positive odd number, how many even numbers are between 5x and 5x + 6?
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Answer:

C

Step-by-step explanation:

If 5x is a positive odd number, using 1 for x would satisfy this.

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You have 6, 8, 10 between those numbers that are even

If you chose 3 for x instead:

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Afina-wow [57]

(3m+5n)(9m²-15mn+25n²)

1) Let's factorize 27m³ +125n³.

27m³ +125n³ <em>Let's use x³ +y³ product to factorize that</em>

<em />

x³ +y³ = (x +y)(x²-xy +y²)

2) So let's rewrite it, since 3³ = 27 and 5³ = 125

27m³ +125n³ =

Plug x =3m and y = 5n into those factors (x +y)(x²-xy +y²)

27m³ +125n³= (3m + 5n)(3²m² -5n*3m +5²n²)

27m³ +125n³= (3m+5n)(9m² - 15mn +25n²)

3) So the answer is

(3m+5n)(9m²-15mn+25n²)

<em />

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