All categories

3 years ago

Find the common difference of the arithmetic sequence -5, -14, -23, ...

Mathematics

2 answers:

BartSMP [9]3 years ago

5 0

Answer:

-9

Step-by-step explanation:

Given :-

A Arithmetic sequence -5 , -14 , -23 ...

And we need to find out the common difference of the Arithmetic sequence . The common difference of a Arithmetic sequence is the number which is added to a term to obtain the next term of the sequence . And it can be obtained by subtracting the consecutive terms.

Sequence :-

$:\implies$ -5 , -14 , -23

Common difference :-

$:\implies$ CD = -14 -(-5) = -14+5=-9

$:\implies$ CD = -23-(-14) = -23+14=-9

Hence the common difference is (-9) .

Vlada [557]3 years ago

4 0

-9 is the right answer I hope you do great

You might be interested in

30 > -6(2X +3) show me how to solve

MA_775_DIABLO [31]

<h3>x > -4 is the solution to this inequality.</h3>

30 > -6(2x + 3)

Distributive property.

30 > -12x - 18

Add 18 to both sides.

48 > -12x

Divide both sides by -12.

(Because we're dividing by a negative, the inequality sign flips.)

6 0

3 years ago

Read 2 more answers

Find the equation of the circle with center at (3, -2) and radius of 3.

kvasek [131]

(x-3) *squared* + (y + 2) *squared* = 6

4 0

3 years ago

The image of a dust mite from a scanning electron microscope is 1.5×10 to the 2nd millimeters wide. The image is 5×10 to 2nd tim

Vinil7 [7]

600 millimeters is the accuracy

7 0

3 years ago

Read 2 more answers

In how many different ways can a red, blue, and green marker be arranged in a tray?

grigory [225]

Answer:

6 ways.

There are one red, one blue and one green maker. So there are 3 markers they are in 3! = 3×2 = 6 ways.

Please mark brainliest! <3

7 0

3 years ago

Johnson Chemicals is considering two options for its supplier portfolio. Option 1 uses two local suppliers. Each has a "unique-e

sashaice [31]

Answer:

a) P=0.0175

b) P=0.0189

Step-by-step explanation:

For both options we have to take into account that not only the chance of a "superevent" will disable both suppliers.

The other situation that will disable both is that both suppliers have their "unique-event" at the same time.

As they are, by definition, two independent events, we can calculate the probability of having both events at the same time as the product of both individual probabilities.

a) Then, the probability that both suppliers will be disrupted using option 1 is

$P_1=P_{se}+P_{ue}^2=0.015+(0.05)^2=0.015+0.0025=0.0175$

b) The probability that both suppliers will be disrupted using option 2:

$P_2=P_{se}+P_{ue}^2=0.002+(0.13)^2=0.002+0.0169=0.0189$

Pue = probability of a unique event

Pse = probability of a superevent

3 0

3 years ago