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3 years ago

Congruence postulates

Mathematics

1 answer:

ZanzabumX [31]3 years ago

6 0

Step-by-step explanation:

Ok, imagine I have a finger pointed up, and you have your's as well. They are not congruent / parallell to each other because they are not in the same plane.

Plane: A plane is kind of the space around you, so take a paper and draw a line, the space around the line is called a plane. To make two lines parallell, they have to be straight and be in the same plane

Congruence/congruent= Equal(led) to

Postulates means that you know it without proof, for example, a right angle is 90 degrees.

There are different congruence postulates. It can be used for triangles or for other shapes.

I hope this answers your question, I am not to sure on what you said !

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Allushta [10]

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2 years ago

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sergejj [24]

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2 years ago

A credit union loaned out $50,000, part at an annual rate of 6% and the rest at an annual rate of 12% . The collected combined i

Natasha_Volkova [10]

Answer: the credit union loaned out $40000 at 6% and $10000 at 12%

Step-by-step explanation:

Let x represent the amount that the

credit union loaned out at the annual rate of 6%.

Let y represent the amount that the

credit union loaned out at the annual rate of 12%.

credit union loaned out $50,000, part at an annual rate of 6% and the rest at an annual rate of 12%. It means that

x + y = 50000

The interest on $x after 1 year would be

6/100 × x = 0.06x

The interest on $y after 1 year would be

12/100 × y = 0.12y

The collected combined interest was $3,600 that year. It means that

0.06x + 0.12y = 3600- - - - - - - - - 1

Substituting x = 50000 - y into equation 1, it becomes

0.06(50000 - y) + 0.12y = 3600

3000 - 0.06y + 0.12y = 3600

- 0.06y + 0.12y = 3600 - 3000

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y = 600/0.06

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5 0

2 years ago

Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [

Darya [45]

Answer:

A=3 and B=6

Step-by-step explanation:

Increasing and Decreasing Intervals of Functions

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

$f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9$

Computing the first derivative:

$f' ( x ) = - 6 x^3 + 54 x - 108$

We find the critical points equating f'(x) to zero

$- 6 x^3 + 54 x - 108=0$

Simplifying by -6

$x^2 -9 x +18=0$

We get the critical points

$x=3,\ x=6$

They define the following intervals

$(-\infty,3),\ (3,6),\ (6,+\infty)$

Thus A=3 and B=6

3 0

3 years ago

Factorise 24p2 + pq - 23q²

Novosadov [1.4K]

24p² + pq - 23q² =

= 24p² + 24pq - 23pq - 23q²

= 24p(p + q) - 23q(p + q)

= (p + q)(24p - 23q)

3 0

3 years ago