2 years ago

What are the polar coordinates of the complex number -23i?

Mathematics

1 answer:

Fantom [35]2 years ago

3 0

<h3>Please markme as Brainliest .......</h3>

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Rewrite the function by completing the square. f(x)= x^{2} -9 x +14f(x)=x 2 −9x+14

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Answer:

$f(x)=(x-4.5)^{2}-6.25$ or $f(x)=(1/4)(2x-9)^{2}-6.25$

Step-by-step explanation:

we have

$f(x)=x^{2}-9x+14$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-14=x^{2}-9x$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-14+4.5^{2}=x^{2}-9x+4.5^{2}$

$f(x)+6.25=x^{2}-9x+4.5^{2}$

Rewrite as perfect squares

$f(x)+6.25=(x-4.5)^{2}$

$f(x)=(x-4.5)^{2}-6.25$

$f(x)=(1/4)(2x-9)^{2}-6.25$

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What are the polar coordinates of the complex number -23i?​

What are the polar coordinates of the complex number -23i?