I’m not a professional but Im guessing I’m correct But a medium pizza has 8 slices if you times that by 5 it equals 40, meaning 2 students didn’t get pizza so you add 2 (5 2/8) making it 42 Students. Answer It’s a mix fraction 5 2/8?. Correct me if I’m wrong
Answer:
f(x)=4x^2
f(2)=4(2)^2
f(2)=4(4)
f(2)=16
2. g(x)=4*2^x
g(2)=4*2^2
g(2)=4*4
g(2)=16
f(2)=g(2)
Both is equal to 16
I hope this help you :)
Step-by-step explanation:
We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:

Where
represents the number of objects/people in the set and
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set


Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
The answer to the question is 25t+26
3.5*(-3)///////3.5*(-3)//////all of this parts same