A. The discriminant is 81. The formula is b^2 - 4ac.
B. 2 answer and both will be rational due to the fact that the discriminant is a perfect square.
C. Solutions are 1/2 and -4. You can find using the quadratic formula.
Answer:
A number line with an open circle on −2, a closed circle on 5, and shading in between
Step-by-step explanation:
solve it you get x>-2
and 3x <=15
x<=5
so its close on 5 and open on -2
Ya i think that it would bee
Answer:
232 in^2
Step-by-step explanation:
80 + 80 + 20 + 20 + 16 + 16 = 232
Check previous answer for better explanation!
Don't touch the center. It is already even.
Start anywhere by connecting a dotted line from one vertex to the next. To keep things so we know what we are talking about, go clockwise. Now you have 2 points that are Eulerized that were not before.
Skip and edge and do the same thing to the next two vertices. Those two become eulerized. Skip an edge and do the last 2.
Let's try to describe this better. Start at any vertex and number them 1 to 6 clockwise.
Join 1 to 2
Join 3 to 4
Join 5 to 6
I think 3 is the minimum.
3 <<<< answer
