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3 years ago

AYOOO HELPPPPP MATHHHH......? THANKKK UUUUU

Mathematics

1 answer:

Gnom [1K]3 years ago

3 0

9514 1404 393

Answer:

choices A and F are part of Leo's system of equations

Step-by-step explanation:

The formula for the amount in an account compounded annually is ...

A = P(1 +r)^t

For the given amounts and variables, that is ...

y = 500(1.025)^x . . . . matches F

The formula for the amount in an account compounded continuously is ...

A = P·e^(rt)

With given values, this is ...

y = 400e^(0.02x) . . . . matches A

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Organize the following polynomial expressions from least to greatest based on their degree: (2 points) I. x + 2xyz II. 3x + y +

sergejj [24]

1) x + 2xyz
2) 3x + y + z
3) 2x³y + y²x - 3x + 4
4) 9x³yz

Least to greatest: 2 , 1, 4, 3,

Let us assume that x = 3; y = 2; z = 1 and we disregard the coefficients
1) x + 2xyz ⇒ 3 + (3)(2)(1) = 9
2) 3x + y + z ⇒ 3 + 2 + 1 = 6
3) 2x³y + y²x - 3x + 4 ⇒ (3³)(2) + (2²)(3) - 3 = 63
<span>4) 9x³yz </span>⇒ (3³)(2)(1) = 54

Least to greatest ; 2) 6 ; 1) 9 ; 4) 54 ; 3) 63.

We disregarded the coefficients because the expressions are organized based mainly on their degree.

5 0

3 years ago

Read 2 more answers

Suppose given △ABD and △CBD.

patriot [66]

Answer:

The required result is proved with the help of angle bisector theorem.

Step-by-step explanation:

Given △ABD and △CBD, AE and CE are the angle bisectors. we have to prove that $\frac{AD}{AB}=\frac{DC}{CB}$

Angle bisector theorem states that an angle bisector of an angle of a Δ divides the opposite side in two segments that are proportional to the other two sides of triangle.

In ΔADB, AE is the angle bisector

∴ the ratio of the length of side DE to length BE is equal to the ratio of the line segment AD to the line segment AB.

$\frac{DE}{EB}=\frac{AD}{AB}$ → (1)

In ΔDCB, CE is the angle bisector

∴ the ratio of the length of side DE to length BE is equal to the ratio of the line segment CD to the line segment CB.

$\frac{DE}{EB}=\frac{CD}{CB}$ → (2)

From equation (1) and (2), we get

$\frac{AD}{AB}=\frac{CD}{CB}$

Hence Proved.

5 0

3 years ago

Christov and Mateus gave out candy to children on Halloween. They each have out candy at a constant rate, and they both gave awa

padilas [110]

Answer: 1) Both gave same number of candies to each child.

2) Christov gave candy to a greater number of children.

Step-by-step explanation:

Since, Christov initially had 300 pieces of candy, and after he was visited by 17 children, he had 249 pieces left.

Let he gave x candy to each student when he visited 17 children.

Then, 17 x + 249 = 300

⇒ 17 x = 51

⇒ x = 3

Since, he distributes candies in a constant speed.

Therefore, his speed of distribution = 3 candies per child

Now,The function that shows the remaining number of candies Mateus has after distributing candies to n children,

C(n)=270 - 3 n

Initially, n = 0

C(0) = 270

⇒ Mateus has initial number of candies = 270

When he gave candies to one child then remaining candies = 270 - 3 × 1 = 267

Thus, the candies, get by a child from Mateus = 270 - 267 = 3

Since, he distributes candies in a constant speed.

⇒ His speed of distribution = 3 candies per child

1) Therefore, Both Christov and Mateus have same speed of distribution.

2) Since, both have same seed.

⇒ The one who has greater number of candies will be distribute more.

⇒ Christov will give more candies.

8 0

3 years ago

-40 represents the height of a subway 40 feet below ground level. 40 represents the height of a kite 40 feet above ground level

Sveta_85 [38]

Answer:

0 represents the ground level

4 0

2 years ago

I need help with this

zhenek [66]

Answer:

6 1/5 = 31/5 and 2 3/4 = 11/4 as improper fractions, hope this helps!

Step-by-step explanation:

7 0

3 years ago

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