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masya89 [10]
3 years ago
9

Write the equation of the graph.

Mathematics
1 answer:
Ber [7]3 years ago
8 0

Answer:

it is the bottom answer or if it was labeled it would be D.

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Dana can type nearly 90 words per minute. Use this information to find the number of hours it will take her to type 2.6 x 105 wo
Vlad1618 [11]

Dana can type 90 words per minute.

Since, 1 minute = \frac{1}{60} hours

Therefore, number of words she can type = \frac{90}{\frac{1}{60}}

                                                                      = 90×60

                                                                      = 5400 words per hour

If she types 2.6\times 10^5 words in 'x' hours.

Number of words Dana types with the given speed in 'x' hours = Speed of typing × Time

= 5400\times x

Therefore, 5400\times x =2.6\times 10^5

5400x=260000

x=\frac{260000}{5400}

x=48.15 hours

Therefore, Dana types 2.6\times 10^5 words in 48.15 hours.

Learn more,

brainly.com/question/621754

6 0
2 years ago
Uhuhuhuu EEEEEEEEEEEEEEEEEEEE help?
lianna [129]

Answer:

4 parts 3

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
$1,200 is deposited into an account with 4.5% simple interest. How much would it earn in interest after 3 years?
zalisa [80]

Answer:

$162

Step-by-step explanation:

$1200 x .045 = $54 x 3 years = $162

8 0
2 years ago
What is the probability a sample of 90 test takers will provide a sample mean test score within 10 points of the population mean
Elena-2011 [213]

Answer:

0.658 is the probability that a sample 90 test takers will provide a sample mean test score within 10 points of the population mean of 502.

Step-by-step explanation:

The following information is missing:

The standard deviation of population is 100.

We are given the following information in the question:

Population mean, μ = 502

Standard Deviation, σ = 100

Sample size, n  = 90

Standard error =

\dfrac{\sigma}{\sqrt{n}} = \dfrac{100}{\sqrt{90}} =  10.54

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(test score within 10 points)

P(492 \leq x \leq 512) \\\\= P(\displaystyle\frac{492 - 502}{10.54} \leq z \leq \displaystyle\frac{512-502}{10.54}) \\\\= P(-0.9487 \leq z \leq 0.9487)\\= P(z \leq 0.9487) - P(z < -0.9487)\\= 0.829 -0.171 = 0.658 = 65.8\%

P(492 \leq x \leq 512) = 65.8\%

0.658 is the probability that a sample 90 test takers will provide a sample mean test score within 10 points of the population mean of 502.

7 0
3 years ago
I know the answer but how do i get it ?
worty [1.4K]
Don't you have to multiply the Area's ? 
5 0
3 years ago
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