Answer:
f = -0.032
Step-by-step explanation:
I looked it up
Assuming the variables are constants, you isolate m. So move am to the left. K-am=emx. Now divide ex. This gives you, m=(K-am/ex)
The answer is A
We have. x=1, then we substitute that on x+z = 20, to solve for z.
1+z=20
z=20-1
z=19
Then we substitute both values x=1 and z=19 on the other equation.
2x +2y+ z = -12
2*1 + 2y + 19= -12
2y= -12 -19-2
2y= -33
y=-33/2
Answer:
P(X > 8) = 0.323
Step-by-step explanation:
We are given that a softball pitcher has a 0.507 probability of throwing a strike for each pitch. Also, the softball pitcher throws 15 pitches.
The above situation can be represented through Binomial distribution;
![P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....](https://tex.z-dn.net/?f=P%28X%3Dr%29%20%3D%20%5Cbinom%7Bn%7D%7Br%7Dp%5E%7Br%7D%20%281-p%29%5E%7Bn-r%7D%20%3B%20x%20%3D%200%2C1%2C2%2C3%2C.....)
where, n = number of trials (samples) taken = 15 pitches
r = number of success = more than 8
p = probability of success which in our question is probability of
throwing a strike for each pitch, i.e., 0.507
<em>LET X = Number of strikes</em>
So, it means X ~ ![Binom(n=15, p=0.507)](https://tex.z-dn.net/?f=Binom%28n%3D15%2C%20p%3D0.507%29)
So, Probability that more than 8 of them are strikes = P(X > 8)
P(X > 8) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)
=
=
= 0.323
Therefore, probability that more than 8 of them are strikes is 0.323.
First u add d and then divide by x