Given :
Challenge given is to volunteer for about 1 1/2 hours per week .
Autum did at a rate of 6 3/4 hours per week .
To Find :
The comparison ( ratio ) her volunteers rate with the challenge rate .
Solution :
Simplifying challenge rate in in normal fraction ,
.
Also , simplifying her rate ,
.
Now , ratio of his work by challenge is :

Therefore , the ratio is 9/2 or 4 1/2 .
Hence , this is the required solution .
Given that the figures are similar polygons, the ratio of their ratios should be equal to the square of the ratio of their circumference. If we let x be the lateral area of the smaller cylinder then,
(x/210π) = (24π/60π)²
The value of x from the equation is,
x = 33.6π
Thus, the area of the smaller cylinder is equal to 33.6π mm².
Answer:100
Step-by-step explanation:
Answer:
<em>Hope the link helps! Sorry I didn't explain. I couldn't find the less than sign. </em>
25 because 3 threes is 9 and 5 twos is 10 so thats 19 plus 6 free throws which are 1 point so a total of 6