Question

Alice and Dave left school at the same time walking in opposite directions. Alice walked at an average speed of 280 ft/min and Dave walked at an average speed of 320 ft/min.How far apart were they in 1 minute?

Answer 1

Answer: they were 600ft apart after 1 minute.

Step-by-step explanation:

Distance = speed × time

Alice and Dave left school at the same time walking in opposite directions.

Alice walked at an average speed of 280 ft/min. It means that the distance covered by Alice in 1 minute is

280 × 1 = 280 ft

Dave walked at an average speed of 320 ft/min. It means that the distance covered by Dave in 1 minute is

320 × 1 = 320 ft

Total distance covered by both Alice and Dave in 1 minute is

280 + 320 = 600 ft

Answer 2

Answer:

600 ft in one minute

i don't know if my answer is correct or not

Step-by-step explanation:

Object 1 280 ft/min => 85 m/min => 85/60 m/sec

sim.

Object 2320 ft/min => 98 m/min => 98/60 m/sec

when two bodies move in opp. direction there speeds are added

so

resultant speed is object 1 + object 2

the resultant comes out as 183/60 m/sec

time is given 1 minute

and we know Distance = time * speed

distance = 183/60 * 60 (183/60 is the speed and 60 is the time in sec as 1 min. = 60sec)

so the distance comes out as 183 m

convert it into ft

1m = 3.2 ft

so 600 ft in one minute