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hichkok12 [17]
3 years ago
12

PLEASE PLEASE HELP ME !!!

Mathematics
2 answers:
frez [133]3 years ago
7 0
The answer is b and c
Ronch [10]3 years ago
6 0

Answer:

It's B and C

Step-by-step explanation:

--> brainly.com/question/16382575

He already explained how to get the answer!

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What is the justification for step 2 in the solution process?12 - x = 7x +32Step 1: -X = 7x + 20Step 2: -8x = 20
HACTEHA [7]
Answer:

The subtraction property of equality

Option A is correct

Explanation:

The given equation is:

12 - x = 7x + 32

Subtract 12 from both sides

12 - 12 - x = 7x + 32 - 12

-x = 7x + 20 (Step 1)

From step 1 above, subtract 7x from both sides

-x - 7x = 7x - 7x + 20

-8x = 20 (Step 2)

Since we subtracted 7x from both sides to get step 2, the justification for step 2 is the subtraction property of equality

6 0
1 year ago
The polynomial f(x) = x³-x²+px+q, where p and q are constants, has remainder 8 when divided by (x-1). If (x+1) is factor of f(x)
quester [9]

Answer:p=-1 and q=1

Step-by-step explanation:

7 0
2 years ago
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The number Of households with VCRs in 1990 was about 87.5% of the number with VCRs in 1993. About how many households had VCRs i
ryzh [129]
I think you answer is 
63/87.5=.72 
<span>.72*100= 72 </span>

<span>Answer is about 72 million </span>

6 0
3 years ago
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The given line passes through the points (0, -3) and (2, 3).
puteri [66]

The equation, in point-slope form of the line that is  parallel to the given line and passes through the point  (-1, -1) is y + 1 = 3(x + 1).

<u>Solution:</u>

Given that, a line passes through (0, -3) and (2, 3).

We have to find the line equation which is parallel to above line and  passes through (-1, -1).

Now, let us find the slope of the given line.

\text { slope } m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}, \text { where }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right) \text { are points on that line }

\text { Then, } m=\frac{3-(-3)}{2-0}=\frac{3+3}{2}=\frac{6}{2}=3

So, slope of given line is 3,  

Then, slope of required line is also 3, as slopes of parallel lines are equal.

Then, required line equation in point – slope form is given as:

\begin{array}{l}{y-y_{1}=m\left(x-x_{1}\right)} \\\\ {y-(-1)=3(x-(-1))} \\\\ {\rightarrow y+1=3(x+1)}\end{array}

Hence, the line equation is y + 1 = 3(x + 1).

6 0
3 years ago
5/9<br> 6.7<br> Write this number as a decimal
kenny6666 [7]

Answer:

0.555555555555555555

7 0
3 years ago
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