1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mashcka [7]
3 years ago
15

25) The area of a trapezium is 330cm2 and the length of one of

Mathematics
2 answers:
Leto [7]3 years ago
6 0

Answer:

Step-by-step explanation:

Grgrwrg

kari74 [83]3 years ago
4 0

Answer

30

steps

area of trapizium is a+b/2 * h.

we have a=14, h=15, area=330 and we need to find b

so, 14+b/2 * 15=330

we divide 15 on both sides so 14+b/2=22

we multiply 2 on both sides so 14+b=44

b=44-14

b=30

You might be interested in
Work out the surface area of this sphere.<br> Give your answer to 1 decimal place.
bearhunter [10]

Answer:

452.4

Step-by-step equation:

surface area of a sphere formula= 4πr²

plug 6 in for r

4π(6)² =452.389 rounded  to 452.4

7 0
3 years ago
Graph y = −x+7. Question 2 Identify the x-intercept.
Phoenix [80]

Answer:

1) Refer to the picture

2) x-intercept = 7

4 0
3 years ago
X=3/5 y=1/3 z=2 4/5 <br><br> work out the value of Z+X x Y
alexandr402 [8]
X=60 Y=33.333~ Z= 80 (I’m pretty sure this is right, but I’m not sure if this is what you wanted/needed) hope this helped^-^
4 0
3 years ago
Which relationship is a direct variation?
Setler79 [48]

Option A is the relationship which shows a direct variation.

Step-by-step explanation:

The direct variation is a relationship between two variables in which one is the multiple of the other. It is given by the relation

\frac{y}{x}=k

Option A:

For x=2 and y=1,

\frac{y}{x}=\frac{1}{2}

For x=4 and y=2,

\frac{y}{x}=\frac{2}{4}= \frac{1}{2}

Since, the constant k is equal for all the values of x and y in the table, this relationship is a direct variation.

Option B:

For x=2 and y=4,

\frac{y}{x}=\frac{4}{2}= 2

For x=4 and y=16,

\frac{y}{x}=\frac{16}{4}  =4

Since, the values of constant k is not equal for all the values of x and y in the table, this relationship is not a direct variation.

Option C:

For x=1 and y=3

\frac{y}{x} =\frac{3}{1} =3

For x=2 and y=5

\frac{y}{x} =\frac{5}{2}

Since, the values of constant k is not equal for all the values of x and y in the table, this relationship is not a direct variation.

Option D:

For x=1 and y=-1

\frac{y}{x} =\frac{-1}{1} =-1

For x=2 and y=2

\frac{y}{x} =\frac{2}{2} =1

Since, the values of constant k is not equal for all the values of x and y in the table, this relationship is not a direct variation.

Thus, Option A is the relationship which shows direct variation.

7 0
3 years ago
To the nearest hundredth, what is the value of x?
Scrat [10]

value of 5 x 6 is 30 or the value of x + y if x = 6 and y = 3 is 9. Value can also refer to a variable or constant

7 0
4 years ago
Read 2 more answers
Other questions:
  • Mike owns two hardware stores. The scatter plots show the number of items sold at a specific price for each store for one week.
    12·2 answers
  • What is the awnser to y=7x?
    12·1 answer
  • How do i solve 5x-9y=-17 and 5x+3y=19 in elimation
    6·1 answer
  • Write 129.701 in expanded form
    10·2 answers
  • Which equation represents a linear function that has a slope of 4/5<br> and a y-intercept of –6?
    9·2 answers
  • A store is having a sale on jelly beans and almonds. For 3 pounds of jelly beans and 8 pounds of almonds, the total cost is $31.
    15·2 answers
  • Five friends went to a baseball game. Three of the friends each bought a ticket for x dollars and a soda for $6.00. The other tw
    8·1 answer
  • 1. Which term best describes the angle below?
    9·1 answer
  • 3. Ben and his friends are going to play putt-putt. At one location, they can pay $2.00 for rentals plus $7.50 per game. At anot
    12·1 answer
  • Express the area of the entire rectangle. Your answer should be a polynomial in standard form.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!