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podryga [215]
3 years ago
12

Specialized high-capacity second storage devices designed to meet organizational demands

Computers and Technology
2 answers:
zzz [600]3 years ago
5 0

Answer:

CD devices

Explanation:

xxTIMURxx [149]3 years ago
3 0

Answer:

Mass storage devices

Explanation:

I don't think I can really explain it, that is just the definition of it.

Elimination:

CD and flash drives aren't high-capacity

Platters aren't really storage devices, they are a part of hard drives

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Problem 1: you must write a method for this problem called sentenceAnalyzer Write a program that reads a sentence from the keybo
forsale [732]

Answer:

   static void sentenceAnalyzer(String sentence){

       int lenOfString = sentence.length()-1;

   

           if(sentence.charAt(lenOfString)=='.'){

               System.out.println("Declarative");

             

           }

           else   if(sentence.charAt(lenOfString)=='?'){

               System.out.println("Interrogative");

             

           }

           else if(sentence.charAt(lenOfString)=='!'){

               System.out.println("Exclamation");

             

           }

           else{

               System.out.println("Unknown");

             

           }

   

   }

Explanation:

Using Java programming language

Create the method as required

Obtain the index of the last element using the string length method

Use if and else statements to check if the character at the last index is equal to any of the characters given and print the expected output

see a complete code with the main method below

<em>import java.util.Scanner;</em>

<em>public class num11 {</em>

<em>    public static void main(String[] args) {</em>

<em>        Scanner in = new Scanner(System.in);</em>

<em>        //Receiving User input</em>

<em>        System.out.println("Enter a sentence");</em>

<em>        String sentence = in.nextLine();</em>

<em>        // Calling the method</em>

<em>        sentenceAnalyzer(sentence);</em>

<em>    }</em>

<em>    static void sentenceAnalyzer(String sentence){</em>

<em>        int lenOfString = sentence.length()-1;</em>

<em />

<em>            if(sentence.charAt(lenOfString)=='.'){</em>

<em>                System.out.println("Declarative");</em>

<em>            }</em>

<em>            else   if(sentence.charAt(lenOfString)=='?'){</em>

<em>                System.out.println("Interrogative");</em>

<em>            }</em>

<em>            else if(sentence.charAt(lenOfString)=='!'){</em>

<em>                System.out.println("Exclamation");</em>

<em>            }</em>

<em>            else{</em>

<em>                System.out.println("Unknown");</em>

<em>            }</em>

<em>    }</em>

<em>}</em>

<em />

8 0
3 years ago
Ania has written this SimpleStopwatch class. In which line is she measuring the elapsed time?
babunello [35]

Answer:

Mona

Explanation:

6 0
2 years ago
Assign testResult with 1 if either geneticMarkerA is 1 or geneticMarkerB is 1. If geneticMarkerA and geneticMarkerB are both 1,
OverLord2011 [107]

Answer:

Following python statement will give the assignment to testResult as specified:

if((geneticMarkerA == 1) or (geneticMarkerB ==1)):

   testResult = 1

if((geneticMarkerA ==1) and (geneticMarkerB == 1)):

   testResult = 0

if((geneticMarkerA == 0) and (geneticMarkerB == 0)):

   testResult = 0

Explanation:

In above statements or and and operator are used to check the conditions of set of values present in variable geneticMarkerA and geneticMarkerB.

Based on if the condition evaluate to true or false respective values to testResult varaible is assigned.

Following is sample run for above statements:

geneticMarkerA = 1

geneticMarkerB = 0

if((geneticMarkerA == 1) or (geneticMarkerB ==1)):

   testResult = 1

if((geneticMarkerA ==1) and (geneticMarkerB == 1)):

   testResult = 0

if((geneticMarkerA == 0) and (geneticMarkerB == 0)):

   testResult = 0

print(testResult)

Output

1

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3 years ago
Utilizando o padrão de medidas e unidades do National Institute of Standards and Technology, em que 1 KB é igual a 1.000 Bytes,
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Segundo o padrão da  National Institute of Standards and Technology a  alternativa correta é a letra E) 400 músicas.  Segundo o padrão disposto acima, dois Giga Bytes equivalem à dois mil Mega Bytes, assim, se cada música tem exatos 5MB, podemos chegar ao total de músicas que podem ser gravadas em um PenDrive de 2GB livres do seguinte modo :

x=\frac{2000 MB}{5MB};x=400

 A evolução da microeletrônica possibilitou uma capacidade de armazenamento cada vez maior a cada ano. O desenvolvimento de novas tecnologias na área permite também que os produtores possam produzir músicas, fotos e vídeos com cada vez mais qualidade (consequentemente mais pesada).

5 0
2 years ago
Producers must understand the marginal benefit of making an additional unit which shows the ...
yan [13]

Producers must understand the marginal benefit of making an additional unit which shows the possible gain. Marginal benefit is used in business and economics as a measurement of the change in benefits over the change in quantity. Possible gain is one example of benefit.  This measurement provides the relevant measurement of benefits at a specific level of production and consumption.

8 0
3 years ago
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