Answer:
What sources? WILL ANSWER in comments
The first thing we are going to do is find the equation of motion:
ωf = ωi + αt
θ = ωi*t + 1/2αt^2
Where:
ωf = final angular velocity
ωi = initial angular velocity
α = Angular acceleration
θ = Revolutions.
t = time.
We have then:
ωf = (7200) * ((2 * pi) / 60) = 753.60 rad / s
ωi = 0
α = 190 rad / s2
Clearing t:
753.60 = 0 + 190*t
t = 753.60 / 190
t = 3.97 s
Then, replacing the time:
θ1 = 0 + (1/2) * (190) * (3.97) ^ 2
θ1 = 1494.51 rad
For (10-3.97) s:
θ2 = ωf * t
θ2 = (753.60 rad / s) * (10-3.97) s
θ2 = 4544,208 rad
Number of final revolutions:
θ1 + θ2 = (1494.51 rad + 4544.208 rad) * (180 / π)
θ1 + θ2 = 961.57 rev
Answer:
the disk has made 961.57 rev 10.0 s after it starts up
Answer:
You could unplug it? LOL
and get a different thermostat.
Explanation:
Could you mark this answer as brainiest?
Thanks! :)
Answer:
Syntax:
For variable_name As [Data Type] = start To end [ Step step ]
For variable_name As [Data Type] = start To end [ Step step ]
[ inner loop statements ]
Next.
[ Outer loop statements ]
Next.
Explanation:
Answer:
1.the program is moved from secondary storage to memory.
Explanation:
Secondary storage media generally have greater storage capacity than RAM (random access memory), for this reason the data and program are stored there.
but ram memories are much faster, for example, a solid state disk (SSD) with SATA III connection can have read and write speeds of approximately 500 MB/s, while a DDR III RAM can have speeds between 12 and 18 GB/S, that is, more than 20 times faster.
So that the flow of data at the time of running a program is optimal, the data from the secondary storage unit is copied to the RAM and this ensures that the speed at which the programs run is at least 20 times faster, and our processes run better.
