Answer:
then x = 2.
Step-by-step explanation:
4 multiplied by 2 = 8
8 divided by 2 equals 4
Putting it together:
4(2)/2=4
Supposing, for the sake of illustration, that the mean is 31.2 and the std. dev. is 1.9.
This probability can be calculated by finding z-scores and their corresponding areas under the std. normal curve.
34 in - 31.2 in
The area under this curve to the left of z = -------------------- = 1.47 (for 34 in)
1.9
32 in - 31.2 in
and that to the left of 32 in is z = ---------------------- = 0.421
1.9
Know how to use a table of z-scores to find these two areas? If not, let me know and I'll go over that with you.
My TI-83 calculator provided the following result:
normalcdf(32, 34, 31.2, 1.9) = 0.267 (answer to this sample problem)
Answer:5 inches wide
Step-by-step explanation:
12-8 (long)=4
9-4 (getting the new drawings length so you subtract)=5
Answer:
Step-by-step explanation:
The first time the basketball bounces it reaches a height of 
.
The second time the basketball bounces it reaches a height of ![(0.722) (0.722) (6) = [(0.722) ^ 2] (6)](https://tex.z-dn.net/?f=%280.722%29%20%280.722%29%20%286%29%20%3D%20%5B%280.722%29%20%5E%202%5D%20%286%29)
. Therefore, after b rebounds the height that the basketball will reach is given by:
