Answer: B) one
This one point is point U since it is on line segment CD. In contrast, a point like point E is not on line CD, so E is not collinear with C and D.
9h < -79 - 2
9h < -81
h < -81/9
h < -9
500* 0.18=90
500-90=410
The tv would be equal to $410.
Hope this helps!
Answer:
The equation of the line segment between points A and X is
![sA + (1-s)X, s\in[0,1]](https://tex.z-dn.net/?f=sA%20%2B%20%281-s%29X%2C%20s%5Cin%5B0%2C1%5D)
Then we need that the point C satisfy:
.
This implies that

We replace the value of s in the equation we get from the second component

Then the point
lies on the line through A and X.