Divide 36 by 3 to get 1/3 of the total, and it says Jim scores 2 times as much so joe scored 12 and Jim scored 24 because 12x2=24. So in conclusion Jim scored 24 and joe scored 12. Hope this helped.
Solve for x:x/5 - 2 = x/2 + 3
Put each term in x/5 - 2 over the common denominator 5: x/5 - 2 = x/5 - (10)/5:x/5 - (10)/5 = x/2 + 3
x/5 - (10)/5 = (x - 10)/5:(x - 10)/5 = x/2 + 3
Put each term in x/2 + 3 over the common denominator 2: x/2 + 3 = x/2 + 6/2:(x - 10)/5 = x/2 + 6/2
x/2 + 6/2 = (x + 6)/2:(x - 10)/5 = (x + 6)/2
Multiply both sides by 10:(10 (x - 10))/5 = (10 (x + 6))/2
10/5 = (5×2)/5 = 2:2 (x - 10) = (10 (x + 6))/2
10/2 = (2×5)/2 = 5:2 (x - 10) = 5 (x + 6)
Expand out terms of the left hand side:2 x - 20 = 5 (x + 6)
Expand out terms of the right hand side:2 x - 20 = 5 x + 30
Subtract 5 x from both sides:(2 x - 5 x) - 20 = (5 x - 5 x) + 30
2 x - 5 x = -3 x:-3 x - 20 = (5 x - 5 x) + 30
5 x - 5 x = 0:-3 x - 20 = 30
Add 20 to both sides:(20 - 20) - 3 x = 20 + 30
20 - 20 = 0:-3 x = 30 + 20
30 + 20 = 50:-3 x = 50
Divide both sides of -3 x = 50 by -3:(-3 x)/(-3) = 50/(-3)
(-3)/(-3) = 1:x = 50/(-3)
Multiply numerator and denominator of 50/(-3) by -1:Answer: x = (-50)/3
Mark mebrisnloest and I will feed u
<h2>
ANSWER:</h2>
<em>I wonder if you have your equation wrong, because(a−b)2=(a−b)(a−b)=a2−ab−ba+b2=a2–2ab+b2</em>
<em> </em>
<em> Your equation, on the other hand, is (a+b)2 and that is not equal to (a−b)2 except when ab=0, i.e. when either a or b equals 0, and that is not what we normally mean by “prove”. Prove would imply “for all values of a and b”, which is not the case in the form you have your equation,</em>
<em><u>hope </u></em><em><u>you </u></em><em><u>undestood</u></em><em><u> </u></em><em><u>what </u></em><em><u>i </u></em><em><u>meant.</u></em><em><u>. </u></em>
<em><u>then </u></em><em><u>plz </u></em><em><u>like </u></em><em><u>and </u></em><em><u>follow </u></em><em><u>me.</u></em><em><u>. </u></em><em><u>♥</u></em>
Answer: 56554
Step-by-step explanation:
