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Veseljchak [2.6K]

3 years ago

6

Stephen record the growth of a plant over 10 weeks for his science project he made a graph that shows how much the plant group e

ach week the plant was 2 inches tall one Stephen started his project at week five plant was 8 inches tall

1 answer:

vazorg [7]3 years ago

5 0

Answer:

y= 6/5x + 2

If you substitute the points (5,8) you get:

8 = 6/5 × 5 + 2

8 = 6 + 2

Step-by-step explanation:

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Write 25x10 to the power of 6 in standard form

Elza [17]

Answer:

25000000 is the correct answer

6 0

2 years ago

miskamm [114]

The x - intercept of 5x - 3y = 15 is (3, 0)

The y -intercept of 5x - 3y = 15 is (0, -5)

<h3><u>Solution:</u></h3>

Given equation is 5x - 3y = 15

<em><u>To find: x - intercept and y -intercept</u></em>

The x intercept is the point where the line crosses the x axis. At this point y = 0

The y intercept is the point where the line crosses the y axis. At this point x = 0.

<em><u>Finding x - intercept:</u></em>

To find the x intercept using the equation of the line, plug in 0 for the y variable and solve for x

So put y = 0 in given equation

5x - 3(0) = 15

5x = 15

x = 3

So the x - intercept is (3, 0)

<em><u>Finding y - intercept:</u></em>

To find the y intercept using the equation of the line, plug in 0 for the x variable and solve for y

So put x = 0 in given equation

5(0) - 3y = 15

-3y = 15

y = -5

So the y - intercept is (0, -5)

5 0

3 years ago

How many solutions does the equation have, x1 + x2 + x3 = 10 , where x1 , x2, and x3 are non-negative integers?

MAVERICK [17]

Non-negative integers are positive integers or zero.

1. When $x_1=0,$ then there are such possible cases for $x_2$ and $x_3:$

$x_2=0,\ x_3=10;$
$x_2=1,\ x_3=9;$
$x_2=2,\ x_3=8;$
$x_2=3,\ x_3=7;$
$x_2=4,\ x_3=6;$
$x_2=5,\ x_3=5;$
$x_2=6,\ x_3=4;$
$x_2=7,\ x_3=3;$
$x_2=8,\ x_3=2;$
$x_2=9,\ x_3=1;$
$x_2=10,\ x_3=0.$

In total 11 solutions for $x_1=0.$

2. For $x_1=1,$ there are such possible cases for $x_2$ and $x_3:$

$x_2=0,\ x_3=9;$
$x_2=1,\ x_3=8;$
$x_2=2,\ x_3=7;$
$x_2=3,\ x_3=6;$
$x_2=4,\ x_3=5;$
$x_2=5,\ x_3=4;$
$x_2=6,\ x_3=3;$
$x_2=7,\ x_3=2;$
$x_2=8,\ x_3=1;$
$x_2=9,\ x_3=0.$

In total 10 solutions for $x_1=1.$

3. This process gives you

for $x_1=2$ - 9 solutions;
for $x_1=3$ - 8 solutions;
for $x_1=4$ - 7 solutions;
for $x_1=5$ - 6 solutions;
for $x_1=6$ - 5 solutions;
for $x_1=7$ - 4 solutions;
for $x_1=8$ - 3 solutions;
for $x_1=9$ - 2 solutions;
for $x_1=10$ - 1 solution.

4. Add all numbers of solutions:

$11+10+9+8+7+6+5+4+3+2+1=66.$

Answer: there are 66 possible solutions (with non-negative integer variables)

8 0

3 years ago

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If a 12 pound turkey takes 4 hours to cook, how long will it take for a 14 pound turkey to cook

zubka84 [21]

It will take the turkey 2 hours to cook

6 0

3 years ago

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Explain why three-dimensional graphs can be misleading. What would be a better type of graph to

scoundrel [369]

three-dimensional graphs wouldn´t give you the right information but two-dimensional graphs would give you the actual size of the shape.

6 0

3 years ago