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Veseljchak [2.6K]
3 years ago
6

Stephen record the growth of a plant over 10 weeks for his science project he made a graph that shows how much the plant group e

ach week the plant was 2 inches tall one Stephen started his project at week five plant was 8 inches tall
Mathematics
1 answer:
vazorg [7]3 years ago
5 0

Answer:

y= 6/5x + 2

If you substitute the points (5,8) you get:

8 = 6/5 × 5 + 2

8 = 6 + 2

Step-by-step explanation:

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Find the value of x.
blagie [28]

Answer:

Step-by-step explanation:

Ask yo teacher for help bih

4 0
2 years ago
What is the image point of (-7,7) after a translation right 1 unit and down 3 units?
ZanzabumX [31]

Answer:

(-6, 4)

Step-by-step explanation

translation rule: (x+1,y-3)

(-7+1, 7-3)

(-6, 4)

6 0
2 years ago
Ok so I’m the answer but how do I get to that answer can someone please help me I am desperate
Svet_ta [14]
X + (x + 10) = 154
2 x + 10 = 154
2 x = 154-10 = 144
x = 72 (ans)
Not sure if it’s right
7 0
3 years ago
Help ! ASAP! I need it done by 10:45
Arturiano [62]

Answer:

13%

Step-by-step explanation:

Its out of 100 people so:

47+33+7 = 87% own a pet

100-87=13%

5 0
2 years ago
LT1 10th grade level
Anton [14]

Answer:

The distance between the pirate and the treasure can be found from the following relationship between ΔEAF and ΔABC;

\overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC} = \overline{EF}/\overline{BC}

Step-by-step explanation:

From the question diagram, we have two triangles, ΔEAF and ΔABC;

The ratio of the lengths of the sides \overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC}

∠EAF and ∠BAC are vertical angles, therefore ∠EAF = ∠BAC

Therefore, ΔEAF and ΔABC are similar triangles by Side-Angle-Side, SAS, rule of similarity which states that two triangles that have ratios of a pair of their corresponding sides and the two sides also form equal angles within each triangle, then the two triangles are similar

Therefore, the ratio of the each pair of corresponding sides of the two triangles are equal

We have;

\overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC} = 50 ft. /(100 ft.) =  \overline{EF}/\overline{BC} = \overline{EF}/120 ft.

\overline{EF} = 120 ft. × 50 ft./(100 ft.) = 60 ft.

\overline{EF} = 60 ft.

The distance between the pirate and the treasure, \overline{EF} = 60 ft.

4 0
3 years ago
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