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Rus_ich [418]
3 years ago
6

How many solutions does this equation have

Mathematics
2 answers:
erastovalidia [21]3 years ago
5 0
No solutions.. 8 doesn’t equal to 10
leva [86]3 years ago
3 0
The best way to solve this equation is to simplify it. So first you’ll distribute the -2 on the left side. This will give you the equation -2t+8=10-2t. Now you bring t to one side by adding 2t to both sides. You will find that t cancels out and you are left with 8=10. Since this statement isn’t true there are no solutions to this equation.
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What is the area of this trapezoid?
dem82 [27]

Answer:

it is c 21 m2

Step-by-step explanation:

My reason is becuase if you multiply 6 and 1 then you 6 and if you multiply 5 and 3 you get 15 so then you add 15 and 6 and then you get 21 means answer is 21 and M2 hope this helps :)

5 0
3 years ago
EXTRA POINTS PLEASE HELP I'LL GIVE BRAINLIEST<br> Please write a 2 column proof :)
lidiya [134]

Answer:

Step-by-step explanation:

1). segment AB ≅ segment AE ......... 1). Given

2). ΔBAE is isosceles .............. 2). Definition of isosceles Δs

3). ∠ABC ≅ ∠AEB ............. 3). Corollary to isosceles Δs theorem

4). segment BG ≅ segment EF ........ 4). Definition of midpoints

5). segment BC ≅ segment ED ......... 5) Given

6). segment CD ≅ segment DC ....... 6). Reflexive property

7). segment BD ≅ segment EC ........ 7). Property of sum of equals parts

8). ΔBGD ≅ Δ EFC ............... 8). SAS postulate

9). ∠1 ≅ ∠2 ............ 9). Corresponding parts of congruent Δs

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7 0
3 years ago
Seven less than the quotient of x and 9
bulgar [2K]
X/9 - 7 is the answer. note x/9 is in fraction form
 

8 0
3 years ago
(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2
Montano1993 [528]

Answer:

\dfrac{m^3}{16p^2q^2}

Step-by-step explanation:

Given:

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}

1.

m^{-1}=\dfrac{1}{m}

2.

q^0=1

3.

2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}

4.

(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}

5.

m^{-1}=\dfrac{1}{m}

6.

2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}

7.

\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}

8.

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}

8 0
3 years ago
If x=y then what does y=x equals? I will give you brainliest if you help me.
MissTica
Yes because they're the same
4 0
3 years ago
Read 2 more answers
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