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Rus_ich [418]
3 years ago
6

How many solutions does this equation have

Mathematics
2 answers:
erastovalidia [21]3 years ago
5 0
No solutions.. 8 doesn’t equal to 10
leva [86]3 years ago
3 0
The best way to solve this equation is to simplify it. So first you’ll distribute the -2 on the left side. This will give you the equation -2t+8=10-2t. Now you bring t to one side by adding 2t to both sides. You will find that t cancels out and you are left with 8=10. Since this statement isn’t true there are no solutions to this equation.
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Long division 25 dived by 2550
Elina [12.6K]

Answer:

25 divided by 2550 = 0.009803922

2550 divided by 25 = 102

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
Simply: x^3 y^3 / x^3 y^2<br><br> ( the arrows mean to the power of the number)
Step2247 [10]

Answer:

y

Step-by-step explanation:


7 0
3 years ago
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7.C.J. says the quotient of -3/4 divided by 1/4 is - 1/3
Elanso [62]

The correct quotient is -3

The mistake CJ likely made is multiplying using the reciprocal of -3/4. The correct option is d. He multiplied using the reciprocal of -3/4

From the question,

We are to determine the correct quotient.

The given division operation to be carried out is -3/4 divided by 1/4

The correct quotient can be determined as shown below

-\frac{3}{4} \div \frac{1}{4}

Multiply -\frac{3}{4} by the reciprocal of \frac{1}{4}

The reciprocal of \frac{1}{4} is  \frac{4}{1}

Then, we get

-\frac{3}{4} \times \frac{4}{1}

This gives

-\frac{12}{4}

= -3

The correct quotient is -3

The mistake CJ likely made is multiplying using the reciprocal of -3/4.

Hence, the correct quotient is -3

The mistake CJ likely made is He multiplied using the reciprocal of -3/4. The correct option is d. He multiplied using the reciprocal of -3/4

Learn more here: brainly.com/question/13124034

6 0
3 years ago
BDсStatementsReasons1. AB || CDAC || BD1. GivenIf two parallel lines are cut by a transversal, then:2. ZABC ZBCDLACB LDBC2.1-13.
Anna11 [10]

The diagram shows statements to prove that both triangles are congruent.

Hence;

\begin{gathered} (2) \\ \angle ABC\cong\angle BCD \\ \angle ACB\cong\angle DBC \\ Alternate\text{ interior angles are congruent } \end{gathered}\begin{gathered} (3) \\ BC\cong BC \\ \operatorname{Re}flexive\text{ property} \end{gathered}\begin{gathered} (4) \\ \Delta ACB\cong\Delta DBC \\ \text{Side}-\text{Angle}-\text{Side} \end{gathered}

Step 1 showed two sides that are congruent for both triangles

Step 2 showed two angles that are congruent

Step 3 showed two sides that are congruent

Therefore, the triangles are congruent by the side-angle-side theorem

6 0
2 years ago
Does anyone know this one !??
Gennadij [26K]

Answer:

I can't see what this says

Step-by-step explanation:

3 0
3 years ago
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