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2 years ago

Find all x-intercepts of the function. Express your answer as a list of x-values. f(x)=x^5−3x^3

Mathematics

1 answer:

Marysya12 [62]2 years ago

3 0

Answer:

Step-by-step explanation:

To determine the x-intercept, we set y equal to zero and solve for x. Similarly, to determine the y-intercept, we set x equal to zero and solve for y.

To find the x-intercept, set y = 0 \displaystyle y=0 y=0.

To find the y-intercept, set x = 0 \displaystyle x=0 x=0.

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How many fives makes 6 tens

Semenov [28]

Answer:

12 fives

Step-by-step explanation:

6 tens is 60, so 60÷5 is 12

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Please help been stuck on this for so long.

suter [353]

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156

Step-by-step explanation:

156

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3 years ago

Can someone pls help ASAP

Vera_Pavlovna [14]

Answer:

89.44

Step-by-step explanation:

using the Pythagorean Theorem: $a^{2} +b^{2}=c^{2}$

$80^{2} +b^{2} =120^{2} \\6400+b^{2} =14400\\b^{2} = 8000\\b = 40\sqrt{5}$

120 is the hypotenuse so it would be c in the equation.

To solve, I simplified and isolated the variable. I got the square root of 8000 simplified (but idk how to write that out lol)

This answer is closest to 89.44

*Hope this helped! Have a great day/ night wherever you are! : )*

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3 years ago

6. Suppose that a fair coin is tossed 2 times, and the result of each toss (H or T) is recorded.

nekit [7.7K]

Answer:

a) $S= {HH, HT, TH, TT}$

b) $P(X=0) = (2C0) (0.5)^0 (1-0.5)^{2-0}= 0.25$

$P(X=1) = (2C1) (0.5)^1 (1-0.5)^{2-1}= 0.5$

$P(X=2) = (2C2) (0.5)^2 (1-0.5)^{2-2}= 0.25$

And we have the following table:

X | 0 | 1 | 2

P(X) | 0.25 | 0.5 | 0.25

Step-by-step explanation:

Let's define first some notation

H= represent a head for the coin tossed

T= represent tails for the coin tossed

We are going to toss a coin 2 times so then the size of the sample size is $2^2 = 4$

a. What is the sample space for this chance experiment?

The sampling space on this case is given by:

$S= {HH, HT, TH, TT}$

b. For this chance experiment, give the probability distribution for the random variable of the total number of heads observed.

The possible values for the number of heads are X=0,1,2. If we assume a fair coin then the probability of obtain heads is the same probability of obtain tails and we can find the distribution like this:

$P(X=0) = (2C0) (0.5)^0 (1-0.5)^{2-0}= 0.25$

$P(X=1) = (2C1) (0.5)^1 (1-0.5)^{2-1}= 0.5$

$P(X=2) = (2C2) (0.5)^2 (1-0.5)^{2-2}= 0.25$

And we have the following table:

X | 0 | 1 | 2

P(X) | 0.25 | 0.5 | 0.25

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2 years ago

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krek1111 [17]

Answer:

-31>v

Step-by-step explanation:

look above there

hope it helps

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2 years ago

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