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Hoochie [10]
3 years ago
10

3 x 7/9 = 21/27? is it correct? Explain why?

Mathematics
2 answers:
andreev551 [17]3 years ago
7 0

Answer:

it is not correct because

<em>3 \times  \frac{7}{9}</em>

<em>is </em><em>like </em><em>saying</em>

<em>\frac{3}{1}  \times  \frac{7}{9}</em>

<em>which </em><em>would </em><em>be </em>

<em>\frac{21}{9}</em>

<em>but </em><em>since </em><em>it </em><em>is </em><em>an </em><em>improper</em><em> </em><em>fraction</em><em> </em><em>you </em><em>have </em><em>to </em><em>change </em><em>it </em><em>to </em><em>a </em><em>mixed </em><em>fraction</em><em> </em><em>which</em><em> </em><em>would</em><em> </em><em>be</em>

<em>2\frac{3}{9}</em>

<em>which </em><em>can </em><em>be </em><em>simplified</em><em> </em><em>to</em>

<em>2\frac{1}{3}</em>

Step-by-step explanation:

hope this was helpful

kompoz [17]3 years ago
6 0

No: first of all, 21/27 is equivalent to 7/9, because you multipied both numerator and denominator by 3.

Secondly, you may write 3 as 3/1, and by doing so it should be clear that you have to multiply numerators and numerator among themselves:

3\cdot \dfrac{7}{9}=\dfrac{3}{1}\cdot \dfrac{7}{9}=\dfrac{3\cdot 7}{9\cdot 1}=\dfrac{21}{9}=\dfrac{7}{3}

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