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Hoochie [10]
3 years ago
10

3 x 7/9 = 21/27? is it correct? Explain why?

Mathematics
2 answers:
andreev551 [17]3 years ago
7 0

Answer:

it is not correct because

<em>3 \times  \frac{7}{9}</em>

<em>is </em><em>like </em><em>saying</em>

<em>\frac{3}{1}  \times  \frac{7}{9}</em>

<em>which </em><em>would </em><em>be </em>

<em>\frac{21}{9}</em>

<em>but </em><em>since </em><em>it </em><em>is </em><em>an </em><em>improper</em><em> </em><em>fraction</em><em> </em><em>you </em><em>have </em><em>to </em><em>change </em><em>it </em><em>to </em><em>a </em><em>mixed </em><em>fraction</em><em> </em><em>which</em><em> </em><em>would</em><em> </em><em>be</em>

<em>2\frac{3}{9}</em>

<em>which </em><em>can </em><em>be </em><em>simplified</em><em> </em><em>to</em>

<em>2\frac{1}{3}</em>

Step-by-step explanation:

hope this was helpful

kompoz [17]3 years ago
6 0

No: first of all, 21/27 is equivalent to 7/9, because you multipied both numerator and denominator by 3.

Secondly, you may write 3 as 3/1, and by doing so it should be clear that you have to multiply numerators and numerator among themselves:

3\cdot \dfrac{7}{9}=\dfrac{3}{1}\cdot \dfrac{7}{9}=\dfrac{3\cdot 7}{9\cdot 1}=\dfrac{21}{9}=\dfrac{7}{3}

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6x5=30
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<span>Hope that helped :)</span>
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4 years ago
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2) Evaluate the given numerical expression.<br><br> A) 9<br> B) 12<br> C) 14<br> D) 21
eduard

Answer:

  • \boxed{\sf{14}}

Step-by-step explanation:

\boxed{\underline{\text{ORDER OF OPERATIONS:}}}

Use the order of operations.

Note: PEMDAS or BODMAS stands for:

<u>PEMDAS</u>

  • <u>Parentheses</u>
  • <u>Exponents</u>
  • <u>Multiply</u>
  • <u>Divide</u>
  • <u>Add</u>
  • <u>Subtract</u>

<u>BODMAS</u>

  • <u>Brackets</u>
  • <u>Order</u>
  • <u>Divide</u>
  • <u>Add</u>
  • <u>Subtract</u>

<u>First, do parentheses.</u>

3+6*(5+4)÷3-7

(5+4)=9

\Longrightarrow: \sf{3+6* 9\div 3-7}

<u>Do multiply and divide.</u>

6*9=54

54/3=18

<u>Then, rewrite the problem down.</u>

\Longrightarrow: \sf{3+18-7}

<u>Add.</u>

\sf{3+18=21}

\sf{21-7=\boxed{\sf{14}}

\Longrightarrow: \boxed{\sf{14}}

  • <u>Therefore, the correct answer is "C. 14".</u>

I hope this helps, let me know if you have any questions.

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Answer:

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Step-by-step explanation:

The given expresion is

5i -  \sqrt{54}

We need to remove the highest perfect square from the radicand.

We rewrite 54 as 6*9

This gives us:

5i -  \sqrt{9 \times 6}

This is the same as

5i -  \sqrt{9}  \times  \sqrt{6}

We now simplify to get:

5i - 3 \sqrt{6}

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Answer:

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Step-by-step explanation:

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