Answer:
So it will take 15 year from 1998 to reach population 229 thousands.
i.e. In 2013 population will be 229 thousand.
Step-by-step explanation:
Given:
Formula model population for city A=146e0.03t
To Find:
Years required to reach population 229 thousands after 1998
Solution:
Using the model ,
A=146e0.03t
here A=229
So equation becomes,
229=146e0.03t
(229/146)=e0.03t
Using log function with base 10 on both sides we get ,
Log(229/146)=log(e^0.03t)
log(1.56489)=0.03tlog(e) .................(using log property log(a^n)=nloga)
0.19548=0.03*t*0.43429
0.19548/0.013028=t
t=(0.19548/0.013028)
t=15.01
t=15 years
So it will take 15 year from 1998 to reach population 229 thousands.
25/100 + 4/10
25/100 + 40/100 = 65/100 of a mile
Answer:
it will take them both 8hr of them working together to make 60 leashes
Step-by-step explanation:
you need to find how much they can make per hour so b can make 3.5 in 1 hr and n can make 4 and 8 is the equivalent that the amount of hrs it takes to make 60 leashes
SOLUTION
From the sequence give
–3, 1, 5, 9, . . .
The first term, a = -3
The common difference, d = 4 (gotten by adding 4 to the next term).
The number of terms required n = 6.
Formula for sum of an arithmetic sequence is given by
Substituting these values into the equation above we have
Hence, the answer is 42, option B
Answer:
t = 2 sec
Step-by-step explanation:
h = – 2t²– 6t + 20
When the rocket hits the ground. h = 0 ft.
– 2t²– 6t + 20 = 0 /: (-2)
t² + 3t - 10 = 0
(t + 5)(t - 2)=0
t = - 5, t = 2
Time can be only positive.