Question

An experiment consists of tossing a coin and rolling a six-sided die simultaneously. Step 1 of 2 : What is the probability of getting a head on the coin and the number 2 on the die

Answer 1

Answer:

$\frac{1}{12}$ probability of getting a head on the coin and the number 2 on the die

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Independent events:

If two events, A and B are independent, the probability of both events happening is the multiplication of the probabilities of each event happening, that is:

$P(A \cap B) = P(A)P(B)$

Probability of getting a head on the coin:

Head or tails, fair coin, so:

$P(A) = \frac{1}{2}$

Probability of getting the number 2 on the die:

6 numbers, one of which is 2, so:

$P(B) = \frac{1}{6}$

What is the probability of getting a head on the coin and the number 2 on the die?

$P(A \cap B) = P(A)P(B) = \frac{1}{2} \times \frac{1}{6} = \frac{1}{12}$

$\frac{1}{12}$ probability of getting a head on the coin and the number 2 on the die