If the diameter of the sphere is increased by 20% . By what % does its curved surface area increase?
1 answer:
Answer:
Curved surface area of sphere = 2πr × 2r=4πr^2;
The new diameter is 120/100 from the old diameter;
2R = (120/100)x(2r);
So, R = 1.2 x r;
Curved surface area of new sphere = 4πR^2 = 4π(1.2xr)^2= 4πr^2x1.44= curved surface of old sphere x (144%);
Finnaly, the increase is 44%.
Step-by-step explanation:
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