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3 years ago

Pls answer professionally or with the right answer I’m beg you

Mathematics

2 answers:

jekas [21]3 years ago

5 0

Answer:

Step-by-step explanation:

Hello friend!!!

here's ur answer

1) <y = 180 - 74 = 106° ( linear pair )

<x = <y ( alternate angles )

therefore, <x = <y = 106°

2) <x = 68° ( corresponding angles )

<y = 180 - 68 = 112° ( linear pair )

<z = 112° ( vertically opposite angles )

Hope this helps

plz mark as brainliest!!!!!

Crazy boy [7]3 years ago

3 0

1) y=106 x=106 2) z=68 y=112 x=112

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A sample of students is taken from the school's A honor roll. The school estimates that there are actually 360 students on the A

Sergio [31]

Answer:

Number of 8th Graders = 360 - X

Step-by-step explanation:

As you can see this question is not complete and lacks the essential data. But we will try to create a mathematical expression to calculate the number of students on the A honor roll which are from 8th grade.

As we know:

Total number of students on the A honor roll = 360

We are asked to calculate, number of students from 8th grade on the A honor roll.

So, let's assume that "X" represents the all the students who are on the A honor roll except 8th grade.

Mathematical Expression:

Number of 8th Graders = Total number of students on the A honor roll - X

Number of 8th Graders = 360 - X

So, if you know the value of X, you can easily calculate the number of students which are from 8th grade on the A honor roll.

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3 years ago

A bike path is 12.5 miles.Dominic is 70% of the way to the end.How far is dominic on the path?

adelina 88 [10]

She is 8.75 miles on the path.

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3 years ago

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Question 5 (5 points)

NNADVOKAT [17]

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3 years ago

It is thought that the front cover and the nature of the first question on mail surveys influence the response rate. An article

denis-greek [22]

Answer:

The null and alternative hypothesis are:

$H_0: \pi_1=\pi_2\\\\H_a:\pi_1\neq \pi_2$

Test statistic z = -0.29

P-value = 0.7709

Fail to reject H0. The data does not suggest that the front cover and nature of the first question on mail surveys influence the response rate.

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the return rate is different for the Plain cover and the Skydiver cover.

Then, the null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2\neq 0$

The significance level is 0.1.

The sample 1 (plain cover), of size n1=209 has a proportion of p1=0.493.

$p_1=X_1/n_1=103/209=0.493$

The sample 2 (skydiver cover), of size n2=215 has a proportion of p2=0.507.

$p_2=X_2/n_2=109/215=0.507$

The difference between proportions is (p1-p2)=-0.014.

$p_d=p_1-p_2=0.493-0.507=-0.014$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{103+109}{209+215}=\dfrac{212}{424}=0.5$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.5*0.5}{209}+\dfrac{0.5*0.5}{215}}\\\\\\s_{p1-p2}=\sqrt{0.001196+0.001163}=\sqrt{0.002359}=0.049$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.014-0}{0.049}=\dfrac{-0.014}{0.049}=-0.29$

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

$\text{P-value}=2\cdot P(z$

As the P-value (0.771) is bigger than the significance level (0.1), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the return rate is different for the Plain cover and the Skydiver cover.

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3 years ago

Let me help u in math skils what is 65x3+4÷7-5=

11Alexandr11 [23.1K]

(4\7=0.57)
(65x3=195)
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4 years ago

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