All categories

3 years ago

36 men can compete a piece of work in 18 days in how many days will 27 men compete the same work

Mathematics

2 answers:

Drupady [299]3 years ago

5 0

Step-by-step explanation:

Explanation:

Less Men, means more Days {Indirect Proportion}

Let the number of days be x then,

27 : 36 :: 18 : x

[Please pay attention, we have written 27 : 36 rather than 36 : 27, in indirect proportion, if you get it then chain rule is clear to you :)]

=>27x = 36 * 18

=> x = 24

So 24 days will be required to get work done by 27 men..

yulyashka [42]3 years ago

3 0

Answer:

36 men can complete work in 18 days

so, one man can complete work in 18×36 days

Therefore, 27 can complete work in 18×36/27 = 24 days

Step-by-step explanation:

You might be interested in

When -3v = -18 is solved, the result is:

rjkz [21]

Answer:

When -3v = -18 is solved, the result is:

21v

4 0

2 years ago

Read 2 more answers

Help me plss to find the area

Delvig [45]

Answer:

A=88 square units

Step-by-step explanation:

A=B x H

A= 11 x 8

A=88 square units

7 0

3 years ago

Find the distance between 4 2/3 and −5 1/3

svetoff [14.1K]

Answer:

The distance between these two is 10.

Step-by-step explanation:

In order to find this, we simply need to subtract the values from one another. If the value is then negative, we take the absolute value to find the distance.

4 2/3 - -5 1/3

4 2/3 + 5 1/3

8 0

3 years ago

Find the indicated values, where g(t)=t^2-t and f(x)=1+x f(2g(1)

Darina [25.2K]

$g(t)=t^2-t\\\\f(x)=1+x\\\\f(2g(1))=?\\\\g(1)=\\_{\text{put t=1 to the equation of g(t)}}\\\\=1^2-1=1-1=0\\---------------\\2g(1)=2(0)=0\\\\f(2g(1))=\\_{\text{put x-0 to the equation of f(x)}}\\\\=1+0=1\\\\Answer:\ f(2g(1))=1$

8 0

3 years ago

Read 2 more answers

Jonathan’s age is one-third Belindas age now in 12 years time Belinda will be M years old

nataly862011 [7]

I’m almost positive your answer is B

5 0

3 years ago

Read 2 more answers

36 men can compete a piece of work in 18 days in how many days will 27 men compete the same work​

36 men can compete a piece of work in 18 days in how many days will 27 men compete the same work