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vivado [14]
2 years ago
14

Triangle ABC is rotated 180 degrees around point B and then dilated to form triangle DBE as shown. Which postulate or theorem es

tablishes that the triangles are similar? AA Similarity SSS Similarity SAS Similarity ASA Similarity
Mathematics
1 answer:
sleet_krkn [62]2 years ago
4 0

Answer:

AAA Similarity

Step-by-step explanation:

Given:

Triangles ABC and DBE

Required

Which postulate shows ABC and DBE similarity

From the question, we understand that the following transformation were done on ABC

  1. Rotation
  2. Dilation

It should be noted that, when a triangle (e.g. triangle ABC) is rotated, the length of the sides and angle measurements remain unchanged.

However, when this triangle is dilated, the sides of the triangle change, but the angles remain unchanged.

Having said that,

When ABC is rotated and dilated to form DBE, we have:

\angle A = \angle D = a

\angle B = \angle B = b

\angle C = \angle E = c

<em>[See Attachment]</em>

<em>Hence, the postulate that answers this question is AAA (Angle-Angle-Angle).</em>

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Answer:

71

Step-by-step explanation:

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3 years ago
1. Given the following diagram. (a) Name the minor arc __________ Name the major arc ___________ (b) If the minor arc is 112°, w
Dmitriy789 [7]

Answer:

a) XY , XVY

b) 248°

c) UV , UY

d) 6√5 = 13.42

Step-by-step explanation:

a) The minor arc is XY

   The major arc is XVY

b) ∵ The measure of the minor arc is 112°

    ∵ The measure of the circle is 360°

    ∴ The measure of the rest arc = 360 - 112 = 248°

c) UV is the tangent to the circle

   UY is the secant to the circle

d) ∵ UV is a tangent to the circle at V

    ∵ UY is a secant to the circle

    ∴ (UV)² = (UX) × (UY)

    ∵ UX = 9 and XY = 11 ⇒ ∴ UY = 11 + 9 = 20

     ∴ (UV)² = 9 × 20 = 180

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6 0
3 years ago
MATH URGENT
maks197457 [2]

{x}^{2}   + 4x - 12 = 0 \\  {x}^{2}  + 4x + 4 - 4 - 12  = 0\\   {(x + 2)}^{2}  - 16 = 0 \\ x =   -   +  \sqrt{16}  - 2 \\ x =   + \:  or - 4 - 2 \\ x =  - 6 \:  \: x = 2
- subtract the 12 from both sides so that it becomes the last constant term in the quadratic equation which should now equal 0.
- take the 4x
- half the coefficient of 4 (2)
- square it (4)
- add it to the equation (+4)
- subtract it from the equation (-4)
- factorise the square (x+2)^2 expands to (x^2 + 4x + 2) as {a+b}^2={a^2 + ab + ba + b^2}
- now the equation is in turning point form.
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- subtract 2 from positive or negative 4 (as -4^2 and 4^2 both equal 16).
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I really hope that this helped :)
7 0
3 years ago
Can someone pls Help me with geometry
RUDIKE [14]

∠P = 6x + 6

∠Q = 2x + 11

∠R = 2x + 3

    ∠P   +    ∠Q     +     ∠R    = 180

(6x + 6) + (2x + 11) + (2x + 3) = 180

                              10x + 20 = 180

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8 0
3 years ago
Find the equation of the straight line parallel to 2y=3x-7 and passing though the point (0.5,-1)
scZoUnD [109]
<span>2y=3x-7 
y = 3/2x - 7/2
y = 1.5x - 3.5 so slope = 1.5
</span><span>line parallel so it has same slope = 1.5
</span>
y +1 = 1.5(x - 0.5)
y + 1 = 1.5x - 0.75
y = 1.5x  - 1.75

answer: equation y = 1.5x  - 1.75
8 0
3 years ago
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