Splitting up the interval [0, 6] into 6 subintervals means we have
![[0,1]\cup[1,2]\cup[2,3]\cup\cdots\cup[5,6]](https://tex.z-dn.net/?f=%5B0%2C1%5D%5Ccup%5B1%2C2%5D%5Ccup%5B2%2C3%5D%5Ccup%5Ccdots%5Ccup%5B5%2C6%5D)
and the respective midpoints are

. We can write these sequentially as

where

.
So the integral is approximately

Recall that



so our sum becomes

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>
<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>
He was wrong because, although three is greater than five, the value of the three is in the ten thousands place, while the five is in the thousands place. Therefore, the correct answer would be that 36594 is greater than 5980.
The correct answer is 720. Just turned it in and got a 100. Good luck and hoped this help ya.
Answer:
J(-5,2), A(-5,4), and N(-1,1)
Step-by-step explanation: