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3 years ago

7

Work out the surface area of this cylinder. Please help, I will award brainliest.

1 answer:

gogolik [260]3 years ago

8 0

Answer:

8*16.8 which is 302.4

Step-by-step explanation:

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Evaluate 8 j − k + 1 4 8j−k+14 when j = 0 . 2 5 j=0.25 and k = 1 k=1.

Nookie1986 [14]

Answer:

Step-by-step explanation:

15

5 0

4 years ago

A running circuit is in the shape of a triangle with lengths of 6km, 6.5km and 7km. What are the sizes of the angles (in minutes

Rudik [331]

A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to $180^{o}$ . The <em>measures</em> of the internal <u>angles</u> of the <u>triangle</u> given in the question are A = $52.6^{o}$ , B = $59.4^{o}$ , and C = $68^{o}$ .

A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to $180^{o}$ .

Considering the given question, let the <u>sides</u> of the triangle be: a = 6 km, b = 6.5 km, and c = 7 km.

Apply the <em>Cosine rule</em> to have:

$c^{2}$ = $a^{2}$ + $b^{2}$ - 2ab Cos C

So that;

$7^{2}$ = $6^{2}$ + $(6.5)^{2}$ - 2(6 * 6.5) Cos C

49 = 36 + 42.25 - 78Cos C

78 Cos C = 78.25 - 49

= 29.25

Cos C = $\frac{29.25}{78}$

= 0.375

C = $Cos^{-1}$ 0.375

= 67.9757

C = $68^{o}$

Apply the <em>Sine rule</em> to determine the <u>value</u> of B,

$\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

$\frac{6.5}{Sin B}$ = $\frac{7}{Sin 68}$

SIn B = $\frac{6.5 *Sin 68}{7}$

= 0.861

B = $Sin^{-1}$ 0.861

= 59.43

B = $59.4^{o}$

Thus to determine the value of A, we have;

A + B + C = $180^{o}$

A + $59.4^{o}$ + $68^{o}$ = $180^{o}$

A = $180^{o}$ - 127.4

= 52.6

A = $52.6^{o}$

Therefore the <u>sizes</u> of the <em>internal angles</em> of the triangle are: A = $52.6^{o}$ , B = $59.4^{o}$ , and C = $68^{o}$ .

For more clarifications on applications of the Sine and Cosine rules, visit: brainly.com/question/14660814

#SPJ1

8 0

2 years ago

How is the graph of the parent function of y = RootIndex 3 StartRoot 0.5 x EndRoot transformed to produce the graph y = RootInde

lana66690 [7]

Answer:

Horizontal stretch by a factor of ½.

Step-by-step explanation:

We were given the parent function as:

$y = \sqrt[3]{0.5x}$

This was transformed to:

$y = \sqrt[3]{x}$

Let

$g(x) = \sqrt[3]{0.5x}$

and

$f(x) = \sqrt[3]{x}$

Then:

$f(x) = g(2x)$

Hence the parent function has been stretched horizontally by a factor of 1/2 to obtain the transformed function.

6 0

3 years ago

Read 2 more answers

Evaluating expressions.

Orlov [11]

3. 101 + x
B. 101 + 12 = 113 pounds
4. d(2p)
B. 14(88) = 1232

Hope this helps!! :)

7 0

3 years ago

two friends travel 150 km and 200 km in time 6 hours and 5 hour respectively. what is the ratio of their average speed?

Minchanka [31]

Answer:

Step-by-step explanation:

5 0

4 years ago