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marusya05 [52]
3 years ago
15

Solve the system of equations y=9x+13 y=2x+48

Mathematics
1 answer:
MakcuM [25]3 years ago
7 0
Both are equal y. So you can set them equal to each other

9x+13=2x+48

Subtract 2x from both sides

7x+13=48
Subtract 13 from both sides

7x= 35

X=5
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Answer:

y - 2 = 3(x + 5)

Step-by-step explanation:

The given equation has slope -1/3.  Any line perpendicular to the given line has a slope which is the negative reciprocal of -1/3, which comes out to +3.

Use the point-slope formula y - k = m(x - h):

y - 2 = 3(x + 5)

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Keith_Richards [23]

5x + 7y + 1 = 0
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find the sum of a 9-term geometric sequence when the first term is 4 and the last term is 1,024 and select the correct answer be
olasank [31]
Hello,

u_{1} =4\\
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 u_{3} =4*q^2\\
...\\

 u_{9} =4*q^8\\\\
==\textgreater\ 4*q^8=1024\\
==\textgreater\ q^8=256\\
==\textgreater\ q=2\mbox{( and there is a problem in the question) } \ or \ q=-2\\
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Answer B (but see the problem)
7 0
3 years ago
Read 2 more answers
Evaluate. 4-6 | 3-5 | /3
riadik2000 [5.3K]

Answer:

0

Step-by-step explanation:

4-6 is -2 and |3-5| is -2 but the |-2| makes it 2 so -2+2=0 so 0/3=0

8 0
3 years ago
Can you solve this problem please​
Afina-wow [57]

Answer:

k = 11

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Given the points are collinear then the slopes between consecutive points are equal.

Using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (5, 1) and (x₂, y₂ ) = (1, - 1)

m = \frac{-1-1}{1-5} = \frac{-2}{-4} = \frac{1}{2}

Repeat with another 2 points and equate to \frac{1}{2}

with (x₁, y₁ ) = (1, - 1) and (x₂, y₂ ) = (k, 4)

m = \frac{4+1}{k-1} , then

\frac{5}{k-1} = \frac{1}{2} ( cross- multiply )

k - 1 = 10 ( add 1 to both sides )

k = 11

6 0
3 years ago
Read 2 more answers
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