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Oliga [24]
3 years ago
5

Given JKL: XYZ, find x.

Mathematics
1 answer:
BabaBlast [244]3 years ago
3 0

Answer:

is there a pic to go along? i need more to this..

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The equation of a parabola is y=x2+6x+9. Write the equation in vertex form.
nignag [31]

Answer:

Step-by-step explanation:

Vertex form is accomplished by completing the square on the quadratic. Do this by first setting the parabola equal to 0 then moving the constant over to the other side:

x^2+6x=-9

Now take half the linear term, square it, and add it to both sides. Our linear term is 6. Half of 6 is 3, and 3 squared is 9:

x^2+6x+9=-9+9

The reason we do this is to create a perfect square binomial on the left:

(x+3)^2=0 (obviously the 0 results from the addition of 9 and -9). Move the 0 back over to the other side and set the quadratic back equal to y:

(x+3)^2+0=y

This gives you a vertex of (-3, 0), which is a minimum value, since the parabola opens upwards.

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3 years ago
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Each of the squares is 1 so that’s 37 plus 8 half’s which is 4 so 37 + 4 = 41
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Step-by-step explanation:

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