The last one, D because it is x+2, which is -2
Your Universe is D, set B ={swimmers}, set C = {weightlifters}.
First, you are looking for what is either swimmers or weightlifters and that is given by the union of sets B and C: B∪C
Then, you have to look for everything that is not swimmers or weightlifters, and that is the complement of the previous set: ¬(B∪C)
An other notation could be everything that is in the Universe which is not a swimmer or a weightlifter: D - (B∪C)
The area will be therefore the one outside the circles.
1st, find the mean of all values. 1+2+3+4=10 10/4=2.5 The mean is 2.5.
2nd, find the distance of each value from the mean. So 2.5-1=1.5; the distance between 1 and 2.5 is 1.5. Repeat it for all of them, and you get 1.5, .5, .5, and 1.5.
3rd, you take each distance and find the mean. 1.5+.5+.5+1.5=4 4/4=1 The mean deviation is 1.
P = 3
Step-by-step explanation:
Multiply both sides by 3
48-9p=2p+15
Add 9p to both sides
48=2p+15+9p48=2p+15+9p
Simplify 2p+15+9p2p+15+9p to 11p+15
48=11p+15
Subtract 15 from both sides
48−15=11p
Simplify 48-15 to 33
33=11p
Divide both sides by 11
\frac{33}11=p11/33=p
Simplify 11/33 to 3
3=p
Switch sides
p=3
Kono Dio Da!!!
1)
34a = 14
a = 14 ÷ 34
a = 7/17
2)
<span>-29 = -32m
-32m = -29
m = 29/32
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