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3 years ago

The function h(t) = 210 – 15t models the altitude of a hot air balloon over time t, in minutes.

2 answers:

8 0

H(10) is the altitude of a hot air balloon overtime after 10 minutes. In order to find h(10)'s value, you just have to substitute 10 as t in the equation. h(10) and h(t) represents the value of y in a linear equation. So pretty much: h(10)= 210 - 15(10). If calculated correctly, h(10)=60.

Snezhnost [94]3 years ago

7 0

Sample response: t represents time, which is the input of the function, so we know that 10 is the time in minutes. h(t) represents the altitude, which is the output of the function after time, t. So, we need to substitute 10 into 210 – 15t in place of t. Simplifying 210 – 15(10), we get that 60 is the altitude in feet. So, after 10 minutes, the hot air balloon is at 60 feet.

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$600 invested with compound interest at a rate of 4% per year for 10 years <br> formula:M= P(1+i)^n

makkiz [27]

Answer: M = 2100$

Explanation:

M = P(1 + I)^n

P = 600$, I = 4% = 0.04, n = 10

=> M = 600(1 + 0.04)^10
M = 600(1.04)^10
M = 600(3.5)
M = 2100$

8 0

2 years ago

(a) How many integers from 1 through 1,000 are multiples of 2 or multiples of 9?

DENIUS [597]

Answer:

(a)There are 500 integers from 1 through 1,000 are multiples of 2.

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)0.611

Step-by-step explanation:

Given the set of Integers from 1 through 1000

The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,

where first term, a =2, common difference, d =2

Nth term of an A.P,

$U_n= a+(n-1)d\\1000=2+2(n-1)\\1000=2+2n-2\\1000=2n\\n=500$

There are 500 integers from 1 through 1,000 are multiples of 2.

Similarly,

Given the set of Integers from 1 through 1000

The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,

where first term, a =9, common difference, d =9

Nth term of an A.P,

$U_n= a+(n-1)d\\999=9+9(n-1)\\999=9+9n-9\\999=9n\\n=111$

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.

There are a total of 1000 numbers between from 1 through 1,000

n(S)=1000

n(Multiples of 2)=500

n(Multiples of 9)=111

Therefore:

$P(\text{Multiples of 9}) \:OR\: P(\text{Multiples of 2})=\frac{111}{1000} + \frac{500}{1000} \\=\frac{611}{1000} \\=0.611$

7 0

3 years ago

it takes 21 minutes for 5 people to paint 7 walls. how many minutes does it take 3 people to paint 10 walls

tensa zangetsu [6.8K]

21/7=3mins per wall with 5 people.
Because we assume that all of the people paint at the same rate, 3 X 5=15 mins for one person working alone.
15/3=5 mins per wall with 3 people X 10 people= 50 mins for 3 people to paint 10 walls.

The answer is 50 mins.

8 0

3 years ago

A population of ants is 10,000 at the start of April. Since then, it triples each month.

Kryger [21]

Answer:

Month since April Number of Ants

0 10,000

1 30,000

2 90,000

3 270,000

4 810,000

Every month, the ant population triples so the multiply the previous population by 3 to find out the new population.

0 months from April = 10,000 * 1 = 10,000 ants

1 month from April = 10,000 * 3 = 30,000 ants

2 months from April = 30,000 * 3 = 90,000 ants

3 months from April = 90,000 * 3 = 270,000 ants

4 months from April = 270,000 * 3 = 810,000

8 0

3 years ago

Please Help Timed Question. Picture provided below.

Jobisdone [24]

Answer:

17.67 mpg

Step-by-step explanation:

The fuel efficiency is given by :

$\eta=1.437+0.541\times s$

We need to find the fuel efficiency for a speed of 30 mph

Put the value of s equals 30 mph in the above equation.

$\eta=1.437+0.541\times 30\\\\\eta=17.67\ mpg$

So, the required fuel efficiency is equal to 17.67 mpg.

6 0

3 years ago