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satela [25.4K]
3 years ago
15

If x+1/x = 2 then x^3 + 1/x^3

Mathematics
2 answers:
son4ous [18]3 years ago
8 0

Answer:

Let p (x) = x + 1 / x = 2

= x + 1 = 2x

= 2x - x = 1

or, x = 1.

let g(x) = x^3 + 1/x^3

since, x = 1

therefore,

g (1) = (1)^3 +1 / (1)^3

= 1 + 1 / 1

= 2 / 1

= 2

So, the answer to your question is 2.

LuckyWell [14K]3 years ago
3 0

x + 1 / x = 2

x × ( x + 1 / x ) = x × 2

x + 1 = 2x

x - x + 1 = 2x - x

x = 1

_________________________________

x^3 + 1 / x^3 =

1^3 + 1 / 1^3 =

1 + 1 / 1 =

2 / 1 =

2

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Aleks [24]

Answer:

AB = 8

Step-by-step explanation:

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BC = 36(7/9)

BC = 4*7

BC = 28

AB + BC = 36

AB = 36 - 28

AB = 8

======

Is AB/BC = 2/7?

8/28 = 2/7  YES

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3 years ago
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Help me expand Expand 2a(a+7)
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Step-by-step explanation:

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Estimate the perimeter and area of the shaded figure to the nearest tenth.
Maru [420]

Answer:

Perimeter = 18.7 units

Area = 13.5 units²

Step-by-step explanation:

Perimeter of ADEC = AD + DE + EC + AC

Length of AD = 3 units

By applying Pythagoras theorem in ΔDBE,

DE² = DB² + BE²

DE² = 3² + 3²

DE = √18

DE = 4.24 units

Length of EC = 3 units

By applying Pythagoras theorem in ΔABC,

AC² = AB² + BC²

AC² = 6² + 6²

AC = √72

AC = 8.49 units

Perimeter of ADEC = 3 + 4.24 + 3 + 8.49

                                 = 18.73 units

                                 ≈ 18.7 units

Area of ADEC = Area of ΔABC - Area of ΔBDE

Area of ΔABC = \frac{1}{2}(AB)(BC)

                       = \frac{1}{2}(6)(6)

                       = 18 units²

Area of ΔBDE = \frac{1}{2}(BD)(BE)

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Area of ADEC = 18 - 4.5

                        = 13.5 units²

6 0
3 years ago
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