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2 years ago

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The measures of two angles of a triangle are 36 degree and 75 degree . The length of the shortest side of a triangle is 10 cm .

The length of longest side of the triangle is:?

1 answer:

Free_Kalibri [48]2 years ago

4 0

Hope it’s helps
You can text me if you don’t understand anything

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The area of a rectangle is 21 in2. The length of the rectangle is 6 in.

IrinaVladis [17]

Given:
Area = 21 in²
length = 6 in.
width = ?

The area of a rectangle is computed by multiplying its length by its width.

A = l * w
21 in² = 6 in * w

To find width, divide the area by its length.

21in²/6in = w
3.5 in. = w.

The width is 3.5 inches.

to check:

Area = Length * Width
21 in² = 6 in x 3.5 in
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2 years ago

3.5b + 6.8k - 5.2b<br> - 2.3k

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Answer:

− 1.7b + 4.5k is the simplified equation. Is that the answer you were looking for?

Step-by-step explanation:

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How many times bigger is 2.7 than 0.03

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2 years ago

The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.4 minutes and a standard deviation of 3.5

Lorico [155]

Answer:

0.6672 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 8.4 minutes

Standard Deviation, σ = 3.5 minutes

We are given that the distribution of distribution of taxi and takeoff times is a bell shaped distribution that is a normal distribution.

According to central limit theorem the sum measurement of n is normal with mean $\mu$ and standard deviation $\sigma\sqrt{n}$

Sample size, n = 37

Standard Deviation =

$=\sigma\times \sqrt{n} = 3.5\times \sqrt{37}=21.28$

P(taxi and takeoff time will be less than 320 minutes)

$P( \sum x < 320) = P( z < \displaystyle\frac{320 - 37(8.4)}{21.28}) = P(z < 0.4323)$

Calculation the value from standard normal z table, we have,

$P(\sum x < 320) =0.6672 = 66.72\%$

0.6672 is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

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3 years ago