Here the answer is: 0.76 and 1.84
I hope I don't have to explain it again.
Answer:
8
Step-by-step explanation:
you just count backwards from 5 until you reach -4
Answer:
0.399
Step-by-step explanation:
The key to doing this problem properly lies in knowing and following order of operations rules.
Here we must perform mult. and div. before addition and subtr., but even before that we must do all work enclosed in parentheses first.
(22.8 × 10–3) is evaluated by doing the mult. first, and then subtracting 3:
(228-3) = 225
and
(5.7 × 10–6) is evaluated by doing the mult. first, then subtracting 6:
(570-6) = 564.
Finally, we divide 225 by 564, obtaining 0.399 (after rounding off to three decimal places).
Answer:
A = 48
Step-by-step explanation:
In this equation, we can factor out the expression
. If we do so, the expression becomes:

We can simplify to get:

and get:

Therefore, A = 48
We are given
Andre rode his bike at a constant speed he rode 1 mile in 5 minutes
Firstly, we will find constant speed
In 5 minutes , distance travelled =1 miles
so, we get speed

Let's assume T is time in minutes
D is the distance in miles
we know that

so, we can plug value
and we get

so, we get
...............Answer