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andreyandreev [35.5K]
3 years ago
12

I NEED MORE HELP MARKING BRAINLIEST!!!!

Mathematics
2 answers:
AlladinOne [14]3 years ago
8 0

Answer:

17, 12, 7, 2, -3

Step-by-step explanation:

The range is just the y-axis values from that function. If you plug in the x values (the domain is the same thing) into the function, you get the y-values which is the range.

Hope this helps!

I GOT YOU BOI DON'T WORRY

myrzilka [38]3 years ago
4 0
The ranges are [17, 12, 7, 2, -3]
(-2,17) (-1,12) (0,7) (1,2) (2,-3)
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Answer:

43.6 * 2.94 = 436/10 * 294/100 = (436 * 294)/1000 = 128184/1000 = 128.184

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URGENT PLEASE HELP !
nasty-shy [4]

Answer:

8/4 Square Inches

Step-by-step explanation:

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1) At a diner, the cost for a specialty waffle and a hashbrown is $9.50. The cost for 2 specialty
klemol [59]

9514 1404 393

Answer:

  • waffle $8
  • hashbrowns $1.50

Step-by-step explanation:

Using w and h for the costs of a waffle and hashbrowns, respectively, we can write the equations for the purchase amounts as ...

  w + h = 9.50

  2w + 3h = 20.50

Subtracting twice the first equation from the second gives ...

  (2w +3h) -2(w +h) = (20.50) -2(9.50)

  h = 1.50 . . . . . . simplify

  w = 9.50 -h = 8.00 . . . . . find w using the first equation

The cost of a waffle is $8.00; the cost of hashbrowns is $1.50.

4 0
3 years ago
How did your position affect the vital capacity of your lungs? Suggest an explanation for any difference you found .
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
One study reports that 34​% of newly hired MBAs are confronted with unethical business practices during their first year of empl
MaRussiya [10]

Answer:

z=\frac{0.28 -0.34}{\sqrt{\frac{0.34(1-0.34)}{116}}}=-1.364  

p_v =2*P(Z  

The p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIl to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace is not significant different from 0.34.  

Step-by-step explanation:

1) Data given and notation

n=116 represent the random sample taken

X represent the number graduates from the previous year claim to have encountered unethical business practices in the workplace

\hat p=0.28 estimated proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace

p_o=0.34 is the value that we want to test

\alpha=0.05 represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is 0.34 or no.:  

Null hypothesis:p=0.34  

Alternative hypothesis:p \neq 0.34  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.28 -0.34}{\sqrt{\frac{0.34(1-0.34)}{116}}}=-1.364  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z  

The p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIl to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace is not significant different from 0.34.  

5 0
3 years ago
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