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Liono4ka [1.6K]
3 years ago
6

What is the y-intercept of the line described below? y=3x+5

Mathematics
2 answers:
dlinn [17]3 years ago
7 0

Answer:

The y-intercept is 5

Step-by-step explanation:

y=mx+b

m is your slope while b is your y-intercept

Therefore your y-intercept is 5

Your Welcome.

Andrews [41]3 years ago
7 0

Answer:

The y intercept is 5

Step-by-step explanation:

Y=MX+B

B= the y intercept.

5 is in the spot for B

Therefor, 5 is the y intercept.

Hope this helps have a great day. :)

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The correlation coefficient r between the age of a homeowner, x, and the number of years remaining on the homeowner's mortgage,
marysya [2.9K]

Solution: We are given that the correlation coefficient between the age of a homeowner, x , and the number of years remaining on the homeowner's mortgage, y, is 0.485

We know that coefficient of determination is the percent of the variation in the dependent variable that is explained by the independent variable. The coefficient of determination is the square of correlation coefficient and is denoted by R^{2}

Therefore, we have:

R^{2}= 0.485^{2}=0.235  or 23.5\% denotes

Hence the option 23.5% is correct

8 0
3 years ago
Sarah earned a grade of 80% on the math exam that had 75 problems. How many correct problems did Sara answer?​
xenn [34]

Answer:

60

Step-by-step explanation:

80/100 times 75 and you will get 60

3 0
3 years ago
Answer the question
kherson [118]
In my opinion 360 would be your closest answer.
3 0
3 years ago
Read 2 more answers
Use Cramer’s rule to solve for x: x + 4y − z = −14 5x + 6y + 3z = 4 −2x + 7y + 2z = −17
V125BC [204]

Looks like the system is

x + 4y - z = -14

5x + 6y + 3z = 4

-2x + 7y + 2z = -17

or in matrix form,

\mathbf{Ax} = \mathbf b \iff \begin{bmatrix} 1 & 4 & -1 \\ 5 & 6 & 3 \\ -2 & 7 & 2 \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} -14 \\ 4 \\ -17 \end{bmatrix}

Cramer's rule says that

x_i = \dfrac{\det \mathbf A_i}{\det \mathbf A}

where x_i is the solution for i-th variable, and \mathbf A_i is a modified version of \mathbf A with its i-th column replaced by \mathbf b.

We have 4 determinants to compute. I'll show the work for det(A) using a cofactor expansion along the first row.

\det \mathbf A = \begin{vmatrix} 1 & 4 & -1 \\ 5 & 6 & 3 \\ -2 & 7 & 2 \end{vmatrix}

\det \mathbf A = \begin{vmatrix} 6 & 3 \\ 7 & 2 \end{vmatrix} - 4 \begin{vmatrix} 5 & 3 \\ -2 & 2 \end{vmatrix} - \begin{vmatrix} 5 & 6 \\ -2 & 7 \end{vmatrix}

\det \mathbf A = ((6\times2)-(3\times7)) - 4((5\times2)-(3\times(-2)) - ((5\times7)-(6\times(-2)))

\det\mathbf A = 12 - 21 - 40 - 24 - 35 - 12 = -120

The modified matrices and their determinants are

\mathbf A_1 = \begin{bmatrix} -14 & 4 & -1 \\ 4 & 6 & 3 \\ -17 & 7 & 2\end{bmatrix} \implies \det\mathbf A_1 = -240

\mathbf A_2 = \begin{bmatrix} 1 & -14 & -1 \\ 5 & 4 & 3 \\ -2 & -17 & 2 \end{bmatrix} \implies \det\mathbf A_2 = 360

\mathbf A_3 = \begin{bmatrix} 1 & 4 & -14 \\ 5 & 6 & 4 \\ -2 & 7 & -17 \end{bmatrix} \implies \det\mathbf A_3 = -480

Then by Cramer's rule, the solution to the system is

x = \dfrac{-240}{-120} \implies \boxed{x = 2}

y = \dfrac{360}{-120} \implies \boxed{y = -3}

z = \dfrac{-480}{-120} \implies \boxed{z = 4}

5 0
2 years ago
How do you find the domain of a table x=1 2 3 4, y= 2 4 3 2
UNO [17]

Answer:

x=+1 y=+2

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
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