Answer:
length=24 inches and width=12 inches
Step-by-step explanation:
Let width of the rectangular sheet be x.
Then its length is twice as width = 2x
From each corner 3-inch square is cut to form a tray.
The length of the tray formed = l = 2x-6 (total length - length of 2 squares cut out from both ends)
The width of the tray formed = b = x-6 (total width - length of 2 squares cut out from both ends)
Height of the tray formed = h = 3 inches
Volume of the tray = l*b*h = (2x-6)*(x-6)*3 = 324 cubic inches.
The length and width of the sheet is 24 and 12 inches respectively.
The number of ways there are to move from (0, 0) to (7, 7) in the coordinate plane with movements of only one unit right or one unit up accordingly is; 49 while that such that y =x is; 7.
<h3>
How many ways are there to get from (0, 0) to (7, 7) in the coordinate plane with pmovements of only one unit right or one unit up?</h3>
It follows from the task content that the movement intended on the coordinate plane is; from (0, 0) to (7, 7).
The number of ways to move such that movements of only one unit right or one unit up is; 7 × 7 = 49.
The number of ways for which y= x is therefore is; 7 as the movement is diagonal.
Read more on coordinate plane;
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The most important thing in this problem is understanding and then dividing the given units properly. The first thing that is given is that the CD makes 58 1/2 revolutions in 3/4 minutes. We have to first simplify the number of revolutions made by the CD. This will make the problem in hand very easy.
Number of revolutions made by the CD = 58 1/2
= 117/2
Then
The unit rate = (117/2)/(3/4)
= (117 * 4)/(2 * 3)
= (117 * 2)/3
= 39 * 2
78
So the unit rate is 78 revolutions per minute.
The first step to solve this problem is to convert the first mixed number to an improper fraction.
÷ 3 +
Dividing is equivalent to multiplying with the reciprocal value,, so next you will need to change the signs.
x
+
Multiply the fractions
+
Finally,, add the two fractions together to get your final answer
This means that the correct answer to your question is
.
Let me know if you have any further questions
:)
Answer: 63lbs
Step-by-step explanation:
The truck can only hold 16crates and each crate weigh 12lbs, the total weight of the 16 crates will be 12×16= 192lbs
This shows that the truck can only contain extra load of 1200lbs - 192lbs = 1008lbs (excluding weight of crates).
To get the shipment weigh close to the total of 1200lbs, the truck must be loaded with engine components not more than 1008lbs.
Since we have 16 crates to fill with engine components not more than 1008lb, each crates will therefore must not exceed 1008/16 pounds of engine components which is equivalent to 63lbs.
Therefore, the manager should instruct the workers to put 63lbs of machine components in "each crate" in order to get the shipment weight as close as possible to 1200 lbs.
