1 because you replace x with 2 so, (2)squared -5x2 + 7 = 4 - 10 + 7 = 1
We will use demonstration of recurrences<span>1) for n=1, 10= 5*1(1+1)=5*2=10, it is just
2) assume that the equation </span>10 + 30 + 60 + ... + 10n = 5n(n + 1) is true, <span>for all positive integers n>=1
</span>3) let's show that the equation<span> is also true for n+1, n>=1
</span><span>10 + 30 + 60 + ... + 10(n+1) = 5(n+1)(n + 2)
</span>let be N=n+1, N is integer because of n+1, so we have
<span>10 + 30 + 60 + ... + 10N = 5N(N+1), it is true according 2)
</span>so the equation<span> is also true for n+1,
</span>finally, 10 + 30 + 60 + ... + 10n = 5n(n + 1) is always true for all positive integers n.
<span>
</span>
Answer:
(1,4)
Step-by-step explanation:
Which ordered pair is a solution of the equation? y = 7 x − 3
a. (1,4) b. (-1,-4) c. both d. neither
Solution
y=7x-3
Solve by trying each ordered pair
a. (1,4)
x=1, y=4
Substituting the value of x and y into the equation
y=7x-3
4=7(1)-3
4=7-3
4=4
This is a true statement
b. (-1,-4)
x=-1, y=-4
Substitute the value into the equation
y=7x-3
-4=7(-1)-3
-4= -7-3
-4= -11
This is not a true statement
This true statement is when x=1 and y=4
So, the ordered pair (1, 4) is the solution
Answer:
N, the verticle lines are are parallel
Step-by-step explanation:
