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stealth61 [152]
2 years ago
7

An unconditional acceptance into a graduate program at a university will be given to students whose GMAT score plus 100 times th

e undergraduate grade point average is at least 1075. ​Robbin's GMAT score was 800. What must her grade point average be in order to be unconditionally accepted into the​ program?
​Robbin's grade point average must be at least ___ in order to be unconditionally accepted into the program. ​
Mathematics
1 answer:
Talja [164]2 years ago
7 0

Answer:

​Robbin's grade point average must be at least 2.75 in order to be unconditionally accepted into the program. ​

Step-by-step explanation:

An unconditional acceptance into a graduate program at a university will be given to students whose GMAT score plus 100 times the undergraduate grade point average is at least 1075

Considering the GMAT score x, and the GPA y, this situation is modeled by the following inequality:

x + 100y \geq 1075

Robbin's GMAT score was 800.

This means that x = 800, and thus:

x + 100y \geq 1075

800 + 100y \geq 1075

100y \geq 275

What must her grade point average be in order to be unconditionally accepted into the​ program?

Solving the above inequality for y:

100y \geq 275

y \geq \frac{275}{100}

y \geq 2.75

Thus:

​Robbin's grade point average must be at least 2.75 in order to be unconditionally accepted into the program. ​

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otez555 [7]

Answer:

30

Step-by-step explanation:

N/-2=-15

N= -15 times -2

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4 0
3 years ago
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Atul has 2/3 lb of candy. Jose has 3/5 lb and Maria has 1/2 lb less then José. How many more pounds of candy does Atul have than
liraira [26]

Given:

Atul has \dfrac{2}{3} lb of candy.

Jose has \dfrac{3}{5} lb of candy.

Maria has \dfrac{1}{2} lb less than Jose.

To find:

How many more pounds of candy does Atul have than Maria?

Solution:

Since, Maria has \dfrac{1}{2} lb less than Jose, therefore

Maria has = \dfrac{3}{5}-\dfrac{1}{2} lb

Maria has = \dfrac{6-5}{10} lb

Maria has = \dfrac{1}{10} lb

Difference between the candies Atul and Maria have.

Difference = \dfrac{2}{3}-\dfrac{1}{10} lb

Difference = \dfrac{20-3}{30} lb

Difference = \dfrac{17}{30} lb

Therefore,  Atul have \dfrac{17}{30} lb of candy more than Maria.

6 0
3 years ago
Please need help on this
zimovet [89]

Answer:

7047, people/km^2

Step-by-step explanation:

To find the answer, you would need to divide the numbers 8550405(people) and 1213.4(kilometers) <--- which where this came from.

Once you divide those numbers, you will directly get the number 7047 as your answer.

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4 0
3 years ago
Connor and Angie helped take attendance during their schools practice fire drill if the actual count was between 77 and 89 inclu
wel

Answer:

The most absolute error is 12

Step-by-step explanation:

The formula for absolute error is given by the following relation;

Absolute error, Δx = Value measured, x₀ - Exact (actual) value, x

Δx = x₀ - x

Since the actual count is between 77 and 89, the maximum absolute error will be where the actual value = 77 and the measured value = 89 and vice versa, giving an absolute error of 89 -77 = 12.

The most absolute error = 12.

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3 years ago
Find y' by implicit differentiation: xy + 2x + 3x^2 = 4
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(xy)' + (2x)' + (3x^2)' = (4)'

y + xy' + 2 + 6x = 0

xy' = -y  -2 -6x

y' = [-y -2 -6x] / x

Now solve y from the original equation and substitue

xy + 2x + 3x^2 = 4 => y = [-2x - 3x^2 + 4] / x

y' =  [(-2x - 3x^2 +4) / x - 2 - 6x ] / x

y' = [-2x - 3x^2 + 4 -2x -6x^2 ] x^2 = [ -4x - 9x^2 + 4] / x^2 =

= [-9x^2 - 4x + 4] / x^2
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3 years ago
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