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Musya8 [376]
3 years ago
15

What is the radius and diameter of the following circle?

Mathematics
2 answers:
alisha [4.7K]3 years ago
8 0

The radius is 16

Diamiter is 32

FromTheMoon [43]3 years ago
7 0

Answer:

Radius = 16cm

Diameter = 32cm

Step-by-step explanation:

The Radius of a circle is half the diameter of the circle. The radius is how far the outside of the circle is from the middle of the circle. To find the Diameter add the radius twice, for example 16+16. Don’t forget your UNIT it is in Centimeters in this case.

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Place the indicated product in the proper location on the grid.<br><br> За^2 x 2а^3​
AlekseyPX

Answer:

when i got the answer i got 12a^25

Step-by-step explanation:

i dont know if this helps

8 0
2 years ago
Evaluate the integral of the quotient of the cosine of x and the square root of the quantity 1 plus sine x, dx.
VMariaS [17]

Answer:

∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c.

Step-by-step explanation:

In order to solve this question, it is important to notice that the derivative of the expression (1 + sin(x)) is present in the numerator, which is cos(x). This means that the question can be solved using the u-substitution method.

Let u = 1 + sin(x).

This means du/dx = cos(x). This implies dx = du/cos(x).

Substitute u = 1 + sin(x) and dx = du/cos(x) in the integral.

∫((cos(x)*dx)/(√(1+sin(x)))) = ∫((cos(x)*du)/(cos(x)*√(u))) = ∫((du)/(√(u)))

= ∫(u^(-1/2) * du). Integrating:

(u^(-1/2+1))/(-1/2+1) + c = (u^(1/2))/(1/2) + c = 2u^(1/2) + c = 2√u + c.

Put u = 1 + sin(x). Therefore, 2√(1 + sin(x)) + c. Therefore:

∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c!!!

4 0
3 years ago
Read 2 more answers
You have been saving nickels, dimes, and quarters in a jar for about a year. You decide to see how much money you've saved up. W
anyanavicka [17]

Answer:

x = number of nickels = 127

y = number of dimes = 156

z = number of quarters = 78

Step-by-step explanation:

Let

x = number of nickels

y = number of dimes

z = number of quarters

Total worth of the coins = $41.45

Total number of coins = 361

x + y + z = 361 (1)

dime = $0.1,

nickel = $0.05

quarter = $0.25

0.05x + 0.1y + 0.25z = 41.45 (2)

twice as many dimes as quarters.

y = 2z

Substitute y = 2z into (1) and (2)

x + 2z + z = 361

0.05x + 0.1(2z) + 0.25z = 41.45

x + 3z = 361

0.05x + 0.2z + 0.25z = 41.45

x + 3z = 361 (3)

0.05x + 0.45z = 41.45 (4)

Multiply (4) by 20

x + 3z = 361 (3)

x + 9z = 829 (5)

Subtract (3) from (5)

9z - 3z = 829 - 361

6z = 468

Divide both sides by 6

z = 468 / 6

= 78

z= 78

Recall,

y = 2z

= 2(78)

= 156

y = 156

Substitute the value of y and z into

x + y + z = 361

x + 156 + 78 = 361

x + 234 = 361

x = 361 - 234

= 127

x= 127

x = number of nickels = 127

y = number of dimes = 156

z = number of quarters = 78

6 0
3 years ago
An equation of a number and 25 equals to the sum of 141 and 159 divided by 2​
Mamont248 [21]

Answer:

25 = 141 + 159/2

Step-by-step explanation:

5 0
3 years ago
Define the domain and range of the function and state whether it is one-to-one, onto, both or neither.
dimulka [17.4K]

Answer:

Neither

Step-by-step explanation:

7 0
3 years ago
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