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Black_prince [1.1K]
2 years ago
6

Whats -3/1 simplified?

Mathematics
1 answer:
wolverine [178]2 years ago
3 0

Answer:

-3

Step-by-step explanation:

You cannot simplify this question anymore, for it is already a whole number.  

Steps:

-3/1

Eliminate the fraction bar and one...

-3

(Anything over one, is whole...so if I were to put 98384743/1, it would just be 98384743.)

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Which equation best describes the same line as y - 6 = -4(x+1)
Kobotan [32]

Answer:

y - 6 = -4(x+1) is equivalent to equation C:  y       =  -4x + 2

Step-by-step explanation:

Solve the given y - 6 = -4(x+1) for y and remove the parentheses shown:

y - 6 = -4(x+1) becomes

y       = -4(x + 1) + 6, or

y       = -4x - 4 + 6, or

y       =  -4x + 2    This is equivalent to equation C.

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3 years ago
BE is the midsegment of triangle ACD. The value of x is:
Anna35 [415]
The midsegment theorem says that the midsegment is half the third side and parallel as well. 20*2 is 40 so x = 35
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2 years ago
If a=[-2 -4 2 5 1 5 -1 -3 -4] and b=[2 3 -5 5 -4 2 -1 -1 3] find ba
Shalnov [3]

The product of A and B matrix will be option D; BA = \left[\begin{array}{ccc}16&10&39\\-32&-30&-18\\-6&-6&-19\end{array}\right].

<h3>What is the multiplication of matrix?</h3>

If A = \left[\begin{array}{ccc}-2&-4&2\\5&1&5\\-1&-3&-4\end{array}\right]and B = \left[\begin{array}{ccc}2&3&-5\\5&-4&2\\-1&-1&3\end{array}\right]

then,

BA = \left[\begin{array}{ccc}2&3&-5\\5&-4&2\\-1&-1&3\end{array}\right] \left[\begin{array}{ccc}-2&-4&2\\5&1&5\\-1&-3&-4\end{array}\right]

BA = \left[\begin{array}{ccc}16&10&39\\-32&-30&-18\\-6&-6&-19\end{array}\right]

Hence, the product of A and B matrix will be option D; BA = \left[\begin{array}{ccc}16&10&39\\-32&-30&-18\\-6&-6&-19\end{array}\right].

Learn more about matrix here;

brainly.com/question/9967572

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6 0
1 year ago
An amoeba is 0.8 millimeter in length. At the science museum there is a scale model of the amoeba that is 160 millimeters in len
lisabon 2012 [21]
The scale factor is 200
4 0
3 years ago
A quality control expert at LIFE batteries wants to test their new batteries. The design engineer claims they have a variance of
iris [78.8K]

Answer:

The probability that the mean battery life would be greater than 533.2 minutes (in a sample of 75 batteries) is \\ P(z>0.48) = P(x>533.2) = 0.3156

Step-by-step explanation:

The main thing we have to take into account in this question is that we are about to find the probability of a <em>sample mean</em>. The distribution for <em>sample means</em> follows a <em>normal distribution</em> with mean \\ \mu and standard deviation \\ \frac{\sigma}{\sqrt{n}}. Mathematically

\\ \overline{x} \sim N(\mu, \frac{\sigma}{\sqrt{n}})

For values of the sample \\ n \ge 30, no matter the distribution the data come from.

And the variable <em>z</em> follows a <em>standard normal distribution</em>, and, as we can remember, this distribution has a mean = 0 and a standard deviation = 1. Mathematically

\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}} [1]

That is

\\ z \sim N(0, 1)

We have a variance of 3364. That is, a <em>standard deviation</em> of

\\ \sigma^2 = 3364; \sigma = \sqrt{3364} = 58

The population mean is

\\ \mu = 530

The sample size is \\ n = 75

The sample mean is \\ \overline{x} = 533.2

With all this information, we can solve the question

The probability that the mean battery life would be greater than 533.2 minutes

Using equation [1]

\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

\\ z = \frac{533.2 - 530}{\frac{58}{\sqrt{75}}}

\\ z = \frac{3.2}{\frac{58}{8.66025}}

\\ z = \frac{3.2}{6.69726}

\\ z = 0.47780

With this value of z we can consult a <em>cumulative standard normal table</em> (or use some statistic program) to find the cumulative probability for <em>z</em> (and remember that this variable follows a standard normal distribution).

Most standard normal tables have values for z for only two decimals, so we can round the previous value for z as z = 0.48.

Then

\\ P(z

However, in the question we are asked for \\ P(z>0.48) = P(x>533.2). As well as all normal distributions, the standard normal distribution is symmetrical around the mean, and we have

\\ P(z>0.48) = 1 - P(z

Thus

\\ P(z>0.48) = 1 - 0.68439

\\ P(z>0.48) = 0.31561

Rounding to four decimal places, we have

\\ P(z>0.48) = 0.3156

So, the probability that the mean battery life would be greater than 533.2 minutes is (in a sample of 75 batteries) \\ P(z>0.48) = P(x>533.2) = 0.3156.

5 0
3 years ago
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