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2 years ago

Whats -3/1 simplified?

Mathematics

1 answer:

wolverine [178]2 years ago

3 0

Answer:

-3

Step-by-step explanation:

You cannot simplify this question anymore, for it is already a whole number.

Steps:

-3/1

Eliminate the fraction bar and one...

-3

(Anything over one, is whole...so if I were to put 98384743/1, it would just be 98384743.)

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Which equation best describes the same line as y - 6 = -4(x+1)

Kobotan [32]

Answer:

y - 6 = -4(x+1) is equivalent to equation C: y = -4x + 2

Step-by-step explanation:

Solve the given y - 6 = -4(x+1) for y and remove the parentheses shown:

y - 6 = -4(x+1) becomes

y = -4(x + 1) + 6, or

y = -4x - 4 + 6, or

y = -4x + 2 This is equivalent to equation C.

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3 years ago

BE is the midsegment of triangle ACD. The value of x is:

Anna35 [415]

The midsegment theorem says that the midsegment is half the third side and parallel as well. 20*2 is 40 so x = 35

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2 years ago

If a=[-2 -4 2 5 1 5 -1 -3 -4] and b=[2 3 -5 5 -4 2 -1 -1 3] find ba

Shalnov [3]

The product of A and B matrix will be option D; BA = $\left[\begin{array}{ccc}16&10&39\\-32&-30&-18\\-6&-6&-19\end{array}\right]$ .

<h3>What is the multiplication of matrix?</h3>

If $A = \left[\begin{array}{ccc}-2&-4&2\\5&1&5\\-1&-3&-4\end{array}\right]$ and $B = \left[\begin{array}{ccc}2&3&-5\\5&-4&2\\-1&-1&3\end{array}\right]$

then,

BA = $\left[\begin{array}{ccc}2&3&-5\\5&-4&2\\-1&-1&3\end{array}\right] \left[\begin{array}{ccc}-2&-4&2\\5&1&5\\-1&-3&-4\end{array}\right]$

BA = $\left[\begin{array}{ccc}16&10&39\\-32&-30&-18\\-6&-6&-19\end{array}\right]$

Hence, the product of A and B matrix will be option D; BA = $\left[\begin{array}{ccc}16&10&39\\-32&-30&-18\\-6&-6&-19\end{array}\right]$ .

Learn more about matrix here;

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1 year ago

An amoeba is 0.8 millimeter in length. At the science museum there is a scale model of the amoeba that is 160 millimeters in len

lisabon 2012 [21]

The scale factor is 200

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3 years ago

A quality control expert at LIFE batteries wants to test their new batteries. The design engineer claims they have a variance of

iris [78.8K]

Answer:

The probability that the mean battery life would be greater than 533.2 minutes (in a sample of 75 batteries) is $\\ P(z>0.48) = P(x>533.2) = 0.3156$

Step-by-step explanation:

The main thing we have to take into account in this question is that we are about to find the probability of a sample mean. The distribution for sample means follows a normal distribution with mean $\\ \mu$ and standard deviation $\\ \frac{\sigma}{\sqrt{n}}$ . Mathematically

$\\ \overline{x} \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

For values of the sample $\\ n \ge 30$ , no matter the distribution the data come from.

And the variable z follows a standard normal distribution, and, as we can remember, this distribution has a mean = 0 and a standard deviation = 1. Mathematically

$\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$ [1]

That is

$\\ z \sim N(0, 1)$

We have a variance of 3364. That is, a standard deviation of

$\\ \sigma^2 = 3364; \sigma = \sqrt{3364} = 58$

The population mean is

$\\ \mu = 530$

The sample size is $\\ n = 75$

The sample mean is $\\ \overline{x} = 533.2$

With all this information, we can solve the question

The probability that the mean battery life would be greater than 533.2 minutes

Using equation [1]

$\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$\\ z = \frac{533.2 - 530}{\frac{58}{\sqrt{75}}}$

$\\ z = \frac{3.2}{\frac{58}{8.66025}}$

$\\ z = \frac{3.2}{6.69726}$

$\\ z = 0.47780$

With this value of z we can consult a cumulative standard normal table (or use some statistic program) to find the cumulative probability for z (and remember that this variable follows a standard normal distribution).

Most standard normal tables have values for z for only two decimals, so we can round the previous value for z as z = 0.48.

Then

$\\ P(z$

However, in the question we are asked for $\\ P(z>0.48) = P(x>533.2)$ . As well as all normal distributions, the standard normal distribution is symmetrical around the mean, and we have

$\\ P(z>0.48) = 1 - P(z$

Thus

$\\ P(z>0.48) = 1 - 0.68439$

$\\ P(z>0.48) = 0.31561$

Rounding to four decimal places, we have

$\\ P(z>0.48) = 0.3156$

So, the probability that the mean battery life would be greater than 533.2 minutes is (in a sample of 75 batteries) $\\ P(z>0.48) = P(x>533.2) = 0.3156$ .

5 0

3 years ago