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zepelin [54]
3 years ago
5

Item 19 The staircase has three parallelogram-shaped panels that are the same size. The horizontal distance between each panel i

s 4.25 inches. What is the area of one panel?
Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
4 0

Answer:

Area = 287\ in^2

Step-by-step explanation:

Given

Length = 20.5

Space = 4.25

Panels = 3

See attachment

Required

The area of one panel

From the attachment, the total width is 50.5in.

i.e.

Total\ Width = 50.5

Given that there are 2 spaces between the 3 panels and each space has a length of 4.25 in.

The reduced width is:

Reduced\ Width = 50.5 - 2 * 4.25

Reduced\ Width = 42

At this point, we can calculate the width of one panel by dividing the reduced width by the number of panels (3).

Width = \frac{42}{3}

Width = 14

The area of one is:

Area = Length * Width

Area = 20.5 * 14

Area = 287\ in^2

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Perform the multiplication. Simplify the answers. 2 √30*( √5+ √6+ √10+ √15)
Delicious77 [7]

The simplified expression of 2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15})is 10\sqrt{6} +  6\sqrt{20}+  20\sqrt{3} +  30\sqrt{2}

The expression is given as:

2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15})

Expand the expression

2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) = 2\sqrt{30} \times \sqrt5+  2\sqrt{30} \times \sqrt6+  2\sqrt{30} \times \sqrt{10} +  2\sqrt{30} \times \sqrt{15}

Factor out 2

2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) = 2(\sqrt{30} \times \sqrt5+  \sqrt{30} \times \sqrt6+  \sqrt{30} \times \sqrt{10} +  \sqrt{30} \times \sqrt{15})

Combine the radicals

2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) = 2(\sqrt{150} +  \sqrt{180}+  \sqrt{300} +  \sqrt{450})

Expand the expression

2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) = 2(\sqrt{25 \times 6} +  \sqrt{9 \times 20}+  \sqrt{100 \times 3} +  \sqrt{225\times 2})

Evaluate the roots

2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) = 2(5\sqrt{6} +  3\sqrt{20}+  10\sqrt{3} +  15 \sqrt{2})

Expand

2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) =10\sqrt{6} +  6\sqrt{20}+  20\sqrt{3} +  30\sqrt{2}

Hence, the simplified expression of 2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15})is 10\sqrt{6} +  6\sqrt{20}+  20\sqrt{3} +  30\sqrt{2}

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