What are the steps to solve this problem in Distributive Property 4(5-2y)

Opposite angles of an inscribed quadrilateral are supplementary?

tangare [24]

Answer:

yes

Step-by-step explanation:

according to cyclic quadrilateral properties the oppoaite angles are supplementry

4 0

3 years ago

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What is cos (x)? 48/58 58/48 26/58 58/26

Evgen [1.6K]

We have to calculate the length of the missing side.
Use the Pythagorean theorem:

$a^2+32^2=58^2\\\\a^2+1024=3364\ \ \ |-1024\\\\a^2=2340\to a=\sqrt{2340}\\\\a=\sqrt{36\cdot65}\\\\a=6\sqrt{65}$

$\cos x=\dfrac{6\sqrt{65}}{58}=\dfrac{3\sqrt{65}}{29}$

I think. Your answers to choice are wrong.

8 0

4 years ago

Jared was given $125.00 to buy 23 packs of strawberries. He came home with the strawberries and $21.50 in change. What was the c

Iteru [2.4K]

Answer: $4.50

Step-by-step explanation:

125=21.50+23x

This is the equation to find this situation since 125 was given and it equals the left over and the spent money.

Subtract 21.50 from both sides first to be epic.

103.5=23x

Very cool! Divide both sides by 23 to get 4.5=x

8 0

3 years ago

The distance between two cities is 180km. The distance was covered by a car at the rate of 50km/h, by a bus 45km/h, by a truck a

Gennadij [26K]

Answer:

The speed and time are directly proportional in that the higher the speed the lesser the time and vice versa.

The constant is the total distance which is 180 km

Step-by-step explanation:

Step one:

given data

The distance between the two cities is 180km

1.The distance was covered by a car at the rate of 50km/h

The time taken will be

velocity= distance/time

time= distance/velocity

time= 180/50

time= 3.6 hours

2.The distance was covered by a bus 45km/h

The time taken will be

velocity= distance/time

time= distance/velocity

time= 180/45

time= 4 hours

3.The distance was covered by a bicycle at 25km/h

The time taken will be

velocity= distance/time

time= distance/velocity

time= 180/25

time= 7.2 hours

7 0

3 years ago

Directions: Answer true or false. If false, provide a counterexample.

Arisa [49]

Natural numbers are closed under division: false.

A set is closed under a certain operation if the results of that operation are always inside that set.

So, if natural numbers were closed under division, the division of two natural numbers would always be a natural number.

You have plenty of counterexamples, to pick one you may divide any odd number by 2: 5/2 is not a natural number.

Negative numbers are closed under addition: true.

Let $m,n$ be two positive numbers. So, $-m,-n$ are two negative numbers. Their sum is

$(-m)+(-n)=-(m+n)$

And since $m+n$ is positive, we deduce that $-(m+n)$ is negative, so the sum of two negative numbers is still negative.

Prime numbers are closed under subtraction: false.

This would mean that the subtraction of two primes is also a prime. Again, there are many counterexamples: 7 is prime and so is 3, but their difference 7-3 is 4, which is not prime.

7 0

3 years ago