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Daniel [21]
2 years ago
15

Hakims car travels 600 feet in 20 seconds. Andres mortar cycle travels 300 feet in 12 seconds. Which is faster, the car or the m

otorcycle?
Find the unit rates

Compare the unit rates

-help please-

Mathematics
2 answers:
sweet [91]2 years ago
8 0

Answer:

Hakims car travels 600 feet in 20 seconds. Andres mortar cycle travels 300 feet in 12 seconds. Which is faster, the car or the motorcycle?

The car is faster

Find the unit rates

The car is going 30 feet in 1 second(600 divide by 20 = 30)

The motorcycle is gonig 25 feet in 1 second(300 divide by 12 = 25)

Compare the unit rates

30 > 25

Step-by-step explanation:

algol [13]2 years ago
4 0

Answer:

Hakim's car is faster.

Step-by-step explanation:

Hakim's car takes 20 seconds to go 600 feet. Andre's motorcycle takes 24 seconds to go 600 feet.

So for Hakim, the unit rate are 30 feet per second because 600/20 = 30

For Andre, the unit rate is 25 feet per second because 600/24 = 25

Hakim's car goes faster because 30 is greater than 25.

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<h3><u>Question 7</u></h3>

<u>Lateral Surface Area</u>

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Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the triangles (bases).

\implies \sf L.A.=2(10 \times 6)+(3 \times 6)=138\:\:m^2

<u>Total Surface Area</u>

Area of the isosceles triangle:

\implies \sf A=\dfrac{1}{2}\times base \times height=\dfrac{1}{2}\cdot3 \cdot \sqrt{10^2-1.5^2}=\dfrac{3\sqrt{391}}{4}\:m^2

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\implies \sf T.A.=2\:bases+L.A.=2\left(\dfrac{3\sqrt{391}}{4}\right)+138=167.66\:\:m^2\:(2\:d.p.)

<u>Volume</u>

\sf \implies Vol.=area\:of\:base \times height=\left(\dfrac{3\sqrt{391}}{4}\right) \times 6=88.98\:\:m^3\:(2\:d.p.)

<h3><u>Question 8</u></h3>

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Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the pentagons (bases).

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8 0
1 year ago
Two buses leave towns 304 miles apart at the same time and travel toward each other. One bus travels 14 mih slower than the othe
8090 [49]

Answer:

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Step-by-step explanation:

Let's define:

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R₂ = rate of bus 2, this is the slower one.

We know that one bus travels 14mi/h slower, then:

R₂ = R₁ - 14mi/h.

Now we know that:

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