Answer:
The common ratio is 
The next term in the sequence is 2
Step-by-step explanation:
In a geometric sequence, the common ratio is the constant value you multiply a term by in order to find the value of the following term. Therefore, it is mathematically calculated as the quotient between a term and the term immediately before it. And it is in fact That is:
common ratio 
This quotient should be true for any two consecutive terms in the sequence.
so using the first two terms, we find:

You can test that this common ratio is true for all other terms listed:

So now, in order to find the term that follows, all we need to do is to multiply the last term given (8) by this common ratio:
