51.Tandin Dorji was married to five women. First woman had three

Mathematics

1 answer:

rosijanka [135]3 years ago

4 0

Answer:

Tandin has 16 children.

Step-by-step explanation:

Total of children:

3+5 = 8(first woman)

2(youngest wife)

1 + 1 = 2(two of the remaining wives)

8 + 2 + 2 = 12

If the ratio of children of 5th wife was 1:3 with the children of other wives.

Thus the 5th wife has 12/3 = 4 children.

How many children does Tandin have?

12 + 4 = 16

Tandin has 16 children.

You might be interested in

How do I solve this?

Norma-Jean [14]

Answer:

Step-by-step explanation:

Base = 25 ft

height = 8 ft

Area of triangle = $\frac{1}{2}*base * height\\\\$

$= \frac{1}{2}*25 *8\\\\= 25 * 4\\\\= 100 ft^{2}$

7 0

3 years ago

Read 2 more answers

Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De

Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable X represent the time a child spends waiting at for the bus as a school bus stop.

The random variable X is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is, $\lambda=\frac{1}{\mu}=\frac{1}{7}$ .

The probability density function of X is:

$f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0$

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

$P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx$

$=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148$