Answer:
Step-by-step explanation:
Find the sum of the first 42 terms of the following series, to the nearest integer.
2,7,12
Solution
The sum is given by
SUM_n=n/2*(a_1+a_n)
a_n=a_1+(n-1)d
a_1=2, n=42, d=5
The 42nd term is therefore given by
a_42=2+(42-1)5=207
SUM_42=42/2*(2+207)=21*209=4389
The sum of the first 42 terms of the series, therefore, is 4389
247 is equal to 200+40+7.
358 is equal to 300+50+8.
To find the answer, add 200+300=500.
40+50=90
7+8=15
500+90+15=605
The answer is 605.
the answer is 1 2 and 3 because they cant be divided by anything
Answer:
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Step-by-step explanation:
