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kvv77 [185]
2 years ago
5

15b^2+20y^3 Find the greatest common factor

Mathematics
1 answer:
Andrew [12]2 years ago
8 0

Answer:

Hope this helps!

Step-by-step explanation:

The GCF is 5

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Write the system of equations represented by the following matrices and matrix equation
MaRussiya [10]
We have:

A=\left[\begin{array}{cc}3&-5\\4&1\end{array}\right]\qquad X=\left[\begin{array}{c}a\\b\end{array}\right]\qquad C=\left[\begin{array}{c}2\\10\end{array}\right]

so:

A\cdot X=C\\\\\\
\left[\begin{array}{cc}3&-5\\4&1\end{array}\right]\cdot\left[\begin{array}{c}a\\b\end{array}\right]=\left[\begin{array}{c}2\\10\end{array}\right]\\\\\\
\left[\begin{array}{c}3a-5b\\4a+1b\end{array}\right]=\left[\begin{array}{c}2\\10\end{array}\right]\\\\\\
\boxed{\begin{cases}3a-5b=2\\4a+b=10\end{cases}}

And the solution of the system of equations:

\begin{cases}3a-5b=2\\4a+b=10\quad|\cdot5\end{cases}\\\\\\
\begin{cases}3a-5b=2\\20a+5b=50\end{cases}\\---------(+)\\\\3a-5b+20a+5b=2+50\\\\3a+20a=52\\\\23a=52\quad|:23\\\\\boxed{a=\dfrac{52}{23}=2\dfrac{6}{23}}\\\\\\
4a+b=10\\\\b=10-4a\\\\b=10-4\cdot\dfrac{52}{23}\\\\\\b=\dfrac{230}{23}-\dfrac{208}{23}\\\\\\\boxed{b=\dfrac{22}{23}}\\\\\\
\boxed{\begin{cases}a=2\dfrac{6}{23}\\\\b=\dfrac{22}{23}\end{cases}}
8 0
3 years ago
In a diagram, KN =4, JN = 20, LN = 10 AND MN = x. Find ML.
Zarrin [17]
I think A) 18 is the right answer.
6 0
3 years ago
Bill and Joe have 60 dollars between them. Bill has half as much as Joe. How much does Bill have?
Katyanochek1 [597]
Bill and Joe have 60 dollars between them. Bill has half as much as Joe.

so Bill = B and Joe = J

20 (B) + 40 (J) = 60

Bill has half the amount of Joe, and so 40/2  = 20

subtract 60 from 20 (the answer for Bill) and you get 40, (the answer for Joe)

hope this helps
6 0
3 years ago
Find the value of X.
SpyIntel [72]

Answer:

<h2>5</h2>

<em>Solution,</em>

<em>For </em><em>kite </em><em>adjacent,</em>

<em>Sides </em><em>are </em><em>equal</em>

<em>6x = 30 \\ or \: x =  \frac{30}{6}  \\ x = 5</em>

<em>hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>

5 0
3 years ago
Read 2 more answers
Let h = for 0   0.01 m, and h = for   0.01 m. (a) find j everywhere. (b) what is j at  = 0? (c) is there a filamentary cu
Katarina [22]
????????????????????????????
4 0
3 years ago
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