Answer:
The answer to the question is
1.5 hours that is;
When the distance between them is more then 135 miles is after 1.5 hours and they will lose radio contact at 3:30 p.m.
Step-by-step explanation:
We note that
The speed of the military convoy headed north =50 mph
The speed of the convoy headed south = 40 mph
Let t be the time taken for the two convoys to be 135 miles apart
The time taken for the two convoys to be 135 miles apart is given by
50×t miles+ 40×t miles= 135 miles
That is 90×t miles = 135 miles
t = 135/90 = 1.5 hrs
You would use order of operations: PEMDAS
P(parenthesis) E(exponents) MD(multiplication/division) AS(addition/subtraction)
with MD and AS order doesnt matter.
8(5-32) you would start with inside the Parenthesis for "P" so (5-32)=(-27)
next you would go to the E but because you dont have an exponent you go to the next step with is the "MD" you have multiplication so next would be 8(-27) and 8 multiplied by -27 is: 8(-27)= -216
ANSWER: -216
Answer:
Step-by-step explanation:
Triangle WXY is a right angle triangle.
From the given right angle triangle
WY represents the hypotenuse of the right angle triangle.
With ∠W as the reference angle,
WX represents the adjacent side of the right angle triangle.
XY represents the opposite side of the right angle triangle.
To determine WY, we would apply the Sine trigonometric ratio
Sin θ = opposite side/hypotenuse. Therefore,
Sin 36 = 5/WY
WY = 5/Sin36 = 5/0.5878
WY = 8.5 to the nearest tenth
hope u get it. I've used RHS to prove LHS
Setting AC = BD because the diagonals are congruent, then 3y/5 = 3y -4
y=5/3
So then AC = 1 = BD