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DanielleElmas [232]
4 years ago
15

The number of acres in a region cleared for farming follows the formula a = f (t) = 2t2 where t is the number of months since th

e region started to be farmed and t ranges from t = 0 to t = 10. Find the average rate of change in the number of acres cleared for farming between t = 1 and t = 4. Give units with your answer
Mathematics
1 answer:
Anit [1.1K]4 years ago
6 0

we are given

a=f(t)=2t^2

we can use average rate of change formula from t=a to t=b

A=\frac{f(b)-f(a)}{b-a}

Here, we are given from t=1 to t=4

so, we will get formula as

A=\frac{f(4)-f(1)}{4-1}

now, we can plug values

A=\frac{2(4)^2-2(1)^2}{4-1}

now, we can simplify it

A=10

the average rate of change in the number of acres cleared for farming between t = 1 and t = 4  is 10 acres/ month.............Answer

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0.8 - 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.697

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And the best option is : 0.697 to 0.903

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

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Solution to the problem

For this case the conditions we have the conditions to assume a normal distribution for the population proportion since:

np=100*0.8=80 >10 , n(1-p) = 10*(1-0.8) =20 >10

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The estimated proportion is given by \hat p =\frac{80}{100} =0.8. If we replace the values obtained we got:

0.8 - 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.697

0.8 + 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.903

The 99% confidence interval would be given by (0.697;0.903)

And the best option is : 0.697 to 0.903

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